WW+JJ+AA=WJA . Solve for W, J, and A. The values must be positive integers and different from each other.
1 answer:
Answer:
W= 1, J=9 and A= 8
Step-by-step explanation:
Given equation: WW+JJ+AA=WJA and the values must be positive integers and different from each other.
Now find the value for W, J, and A.
The two digit number has 10th digit and unit digit
∴ WW=
JJ=
AA=
In equation we can write as
Similary for three digit number, it has 100th digit, 10th digit and unit digit.
∴ WJA=
In the given equation we can write as
Solving the equation now,
Subtracting 11W, 10J and A on both side
⇒
Remember, the values must be positive integers and different from each other.
Now using the value between 1 to 9 to make equation equal.
If we use 1 for W, 8 for A and 9 for J
⇒
⇒
∴ Value will be W= 1, J= 9 and A= 8.
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Step-by-step explanation:
We have,
If a quadratic equation with real coefficients has a discriminant of -36.
The general form of quadratic equation is :
The discriminant of this equation is :
If D=0, it will have 1 real roots
If D>0, it will have 2 real roots
If D<0, it will have no real roots
We have,
D = -36 < 0, so, the quadratic equation will have no real roots.
2) 5.625 mg will be left
Explanation:1) Half-life = 17.5 days
initial amount of Arsenic-74 = 90 mg
To get the equation, we will use the equation of half-life:
2) we need to find the remaining amount of Arsenic-74 after 70 days
t = 70
So after 70 days, 5.625 mg will be left