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3 years ago

WW+JJ+AA=WJA . Solve for W, J, and A. The values must be positive integers and different from each other.

Mathematics

1 answer:

stira [4]3 years ago

3 0

Answer:

W= 1, J=9 and A= 8

Step-by-step explanation:

Given equation: WW+JJ+AA=WJA and the values must be positive integers and different from each other.

Now find the value for W, J, and A.

The two digit number has 10th digit and unit digit

∴ WW= $10W+W= 11W$

JJ= $10J+J= 11J$

AA= $10A+A= 11A$

In equation we can write as $11W+11J+11A= WJA$

Similary for three digit number, it has 100th digit, 10th digit and unit digit.

∴ WJA= $100W+10J+A$

In the given equation we can write as $11W+11J+11A= 100W+10J+A$

Solving the equation now,

$11W+11J+11A= 100W+10J+A$

Subtracting 11W, 10J and A on both side

⇒ $J+10A= 89W$

Remember, the values must be positive integers and different from each other.

Now using the value between 1 to 9 to make equation equal.

If we use 1 for W, 8 for A and 9 for J

⇒ $9+10\times 8= 89\times 1$

⇒ $89=89$

∴ Value will be W= 1, J= 9 and A= 8.

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1 year ago

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