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Lerok [7]
3 years ago
5

I need help. I’m stuck on this question. Help ASAP!

Chemistry
2 answers:
muminat3 years ago
5 0

atomic number i believe is the answer

Mice21 [21]3 years ago
4 0

The number of protons in the nucleus of an atom of an element is the <u>atomic number</u> of that element.

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In the conclusion to the snake mole lab, you have to convert 3.45 moles of (NH4)2S04 to
Serhud [2]
Molar mass = 132.14g/mol
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3 years ago
Nicotine is a poisonous, addictive compound found in tobacco. A sample of nicotine contains 6.16 mmol of C, 8.56 mmol of H, and
tiny-mole [99]

C₁₀H₁₄N₂ is the empirical formula.

In chemistry, the empirical formula of a chemical compound is the simplest whole number ratio of atoms present in a compound.

<h3>Tell us about the empirical formula.</h3>

The empirical formula of a chemical compound in chemistry is the simplest whole number ratio of atoms in a compound. Two simple instances of this concept are the empirical formulas of sulfur monoxide (SO) and disulfur dioxide (S2O2).

Its empirical formula is the simplest whole number ratio of each type of atom in the compound. Data about the mass of each component in a compound or the composition's percentage can be used to calculate it.

To learn more about empirical formula visit:

brainly.com/question/14044066

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8 0
2 years ago
A principal quantum number refers to
jok3333 [9.3K]
<span> this represents the relative overall energy of each orbital, and the energy of each orbital increases as the distance from the nucleus increases</span>
6 0
3 years ago
Read 2 more answers
A green rat snake that lives in the grass and a brown rat snake that lives in the desert is a form of what ?
liberstina [14]

A green rat snake that lives in the grass and a brown rat snake that lives in the desert is a form of geographically separated species.

Explanation:

The habitats of the green rat snake  and brown rat snake shows that they are geographically separated species.

The two rat snakes are different species because of their distinct habitat and morphology.

When two species get separated by habitat their breeding method changes either by morphology or breeding pattern.

Such species do not produce viable offspring.

Thus a green rat snake and a brown rat snake have very different habitats they are now two different species.

Such species are said to be reproductively isolated species. Two species having genetic divergence undergo natural selection to adapt to the environment.

6 0
4 years ago
The formation of nitryl fluoride, 2no2(g)+f2(g)⇌2no2f(g) is first order in no2 and first order in f2. if the concentration of no
ra1l [238]
The reaction is:

2 NO₂ (g) + F₂ (g) ⇆  2 NO₂F (g)

The stoichiometric coefficients of the substances balance out each other to obey the Law of Definite Proportions. Now, you have to note that determining the reaction rate expression is specific to a certain type of reaction. So, this are determined empirically through doing experiments. But in chemical reaction engineering, to make things simple, you assume that the reaction is elementary. This means that the order of a reaction with respect to a certain substance follows their individual stoichiometric coefficients. What I'm saying is, the stoichiometric coefficients are the basis of our reaction rate orders. For this reaction, the rate order is 2 for NO₂, 1 for F₂ and 2 for NO₂F. When the forward and reverse reactions are in equilibrium, then it applies that:

Reaction rate of disappearance of reactants = Reaction rate of formation of products.

Therefore, we can have two reaction rate constants for this. But since the conditions manipulated are the reactant side, let's find the expression for reaction rate of disappearance of reactants.

-r = k[NO₂]²[F₂]

The negative sign before r signifies the rate of disappearance. If it were in terms of the product, that would have been positive. The term k denotes for the reaction rate constant. That is also empirical. As you can notice the stoichiometric coefficients are exponents of the concentrations of the reactants. Let's say initially, there are 1 M of NO₂ and 1 M of F₂. Then,

-r = k(1)²(1)
-r = k

Now, if we change 1 M of NO₂ by increasing it to its half, it would now be 1.5 M NO₂. Then, if we quadruple the concentration of F₂, that would be 4 M F₂. Substituting the values:

-r = k(1.5)²(4)
-r = 9k

So, as you can see the reaction rate increase by a factor of 9.
4 0
4 years ago
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