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3 years ago

I WILL RATE BRAINLIEST I JUST NEED HELP!!!!

2 answers:

8 0

15:15 which cancels to 1:1 so for each mole of co2 u get a mole of carbon monoxide

brainliest and thanks plz:)))))))))))

Marina CMI [18]3 years ago

8 0

Hello.

The reaction is:

$\mathsf{5 Fe_{3}O_{2} + 15 CO \to 15 CO_{2}}$

$\mathsf{Ratio = \dfrac{15}{15} = 1}$

The mole ration of carbon dioxide to carbon monoxide is 1, as for every mole of carbon monoxide, there is one mole of carbon dioxide.

Hope I helped.

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Will mark Brainly us if you help me

ohaa [14]

Answer: ok, its C

Explanation: I used D=26.4* 3 to calculat it

5 0

3 years ago

1. When iron is oxidized, what is reduced?

lys-0071 [83]

Answer:Oxygen

Explanation:

Oxygen gets reduced when iron is oxidized.

3 0

3 years ago

Read 2 more answers

Consider the first-order reaction described by the equation At a certain temperature, the rate constant for this reaction is 5.8

zubka84 [21]

Answer: The half life of the reaction is 1190.7 seconds

Explanation:

The equation used to calculate rate constant from given half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

k = rate constant of the reaction = $5.82\times 10^{-4}s^{-1}$

$t_{1/2}$ = half life of the reaction = ?

Putting values in above equation, we get:

$t_{1/2}=\frac{0.693}{5.82\times 10^{-4}s^{-1}}=1190.7s$

Hence, the half life of the reaction is 1190.7 seconds

8 0

3 years ago

Which of the following statements explain why the van der Waals equation must be used to describe real gases? X. interactions be

8090 [49]

Answer:

Statements Y and Z.

Explanation:

The Van der Waals equation is the next one:

$nRT = (P + \frac{an^{2}}{V^{2}})(V -nb)$ (1)

The ideal gas law is the following:

$nRT = PV$ (2)

where n: is the moles of the gas, R: is the gas constant, T: is the temperature, P: is the measured pressure, V: is the volume of the container, and a and b: are measured constants for a specific gas.

As we can see from equation (1), the Van der Waals equation introduces two terms that correct the P and the V of the ideal gas equation (2), by the incorporation of the intermolecular interaction between the gases and the gases volume. The term an²/V² corrects the P of the ideal gas equation since the measured pressure is decreased by the attraction forces between the gases. The term nb corrects the V of the ideal gas equation, taking into account the volume occuppied by the gas in the total volume, which implies a reduction of the total space available for the gas molecules.

So, the correct statements are the Y and Z: the non-zero volumes of the gas particles effectively decrease the amount of "empty space" between them and the molecular attractions between gas particles decrease the pressure exerted by the gas.

Have a nice day!

5 0

3 years ago

How many grams of ethylene glycol (C2H6O2) must be added to 1.15 kg of water to produce a solution that freezes at -4.46Â°C?

jok3333 [9.3K]

Answer:

232.5 g C2H6O2

Explanation:

The equation you need to use here is ΔTf = i Kf m

Since pure water freezes at 0 C, your ΔTf is just 4.46 C

i = 1 (ethylene glycol is a weak electrolyte)

Kf = molal freezing constant, which for water is 1.86 C/m

m = molality = x mols C2H6O2 / 1.15 kg H2O (don't know the moles of ethylene glycol we're dissolving yet)

Than,

4.46 C = 1.86 C/m (x mol C2H6O2 / 1.15 kg H2O)

Solve for x, you should get x = 2.75 mol C2H6O2

3.75 mol C2H6O2 (62 g C2H6O2 / 1 mol C2H6O2) = 232.5 g C2H6O2

7 0

3 years ago