3 years ago

Can someone please help thanks

Mathematics

1 answer:

Eddi Din [679]3 years ago

3 0

That = that could mean 599

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BRAINLIEST 100 PTS MATH HELP PLEASE

denis-greek [22]

Answer:

they are 10km 32 degrees far from each other

Step-by-step explanation:

scott - 100km - 30 degrees

spork - 110km - 62 degrees

how far = difference between them

as spork's distance and degrees are greater than scott we substract Scott's from spork's

110 - 100 = 10 km

62 - 30 = 32 degrees

they are 10km 32 degrees far from each other

6 0

2 years ago

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Leno4ka [110]

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4 years ago

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Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Let f(x) = x2 + x + 2 and g(x) = 2x2 + 5. Find f(g(x)). Show each step of your work.

OlgaM077 [116]

$f(g(x))=(2x^2+5)^2+2x^2+5+2\\
f(g(x))=4x^4+20x^2+25+2x^2+7\\
f(g(x))=4x^4+22x^2+32
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4 years ago

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How many roots of the polynomial 30x^4 + 7x^3-125x^2-54x+72 have absolute value greater than 1?

Daniel [21]

Answer:

There are 3 roots of the given polynomial that have absolute value greater than 1.

Step-by-step explanation:

We are given the polynomial:

$p(x) = 30x^4 + 7x^3-125x^2-54x+72$

We can factorize the given polynomial as:

$p(x) = 30x^4 + 7x^3-125x^2-54x+72\\=(x-2)(2x+3)(5x-3)(3x+4)=0$

$\text{Solving for}\\(x-2) = 0\\x = 2\\|x| = 2 > 1$

$\text{Solving for}\\(2x+3) = 0\\x = \dfrac{-3}{2}\\\bigg|\dfrac{-3}{2}\bigg| = \dfrac{3}{2} > 1$

$\text{Solving for}\\(5x-3) = 0\\x = \dfrac{3}{5}\\\bigg|\dfrac{3}{5}\bigg| = \dfrac{3}{5} < 1$

$\text{Solving for}\\(3x+4) = 0\\x = \dfrac{-4}{3}\\\bigg|\dfrac{-4}{3}\bigg| = \dfrac{4}{3} > 1$

Thus, there are 3 roots of the given polynomial that have absolute value greater than 1.

8 0

4 years ago