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kotegsom [21]
3 years ago
14

Answerrrrrrrrrrrrrrrrr

Mathematics
1 answer:
Keith_Richards [23]3 years ago
5 0
I think it is 20x + 72 I think that’s right!!
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Find the missing number based on the description below:
Nat2105 [25]

Answer:

The number is -2

Step-by-step explanation:

12 less than 7 times a number can be express as follows,

let the number = a

7a - 12

According to the question the number 7a - 12 is equals to 32 less than the product of - 3 and the number.

32 less than the product of -3 and the number can be express below.

-3a - 32. Therefore,

7a - 12 = -3a - 32

collect like terms

7a + 3a = - 32 + 12

10a = -20

divide both sides by 10

a = -20/10

a = -2

The number is -2

8 0
4 years ago
Simplify 8.3-4.5(6.1+.5)
klemol [59]

The answer is -21.4

Hope that answers your question ;)

3 0
3 years ago
Find the complex zeros of each polynomial function. Use your results to write the polynomial as a product of linear factors. Tha
mart [117]

here you are the answer.

7 0
1 year ago
Determine the zeroes of the polynomial
Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)}  \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)}  -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\

\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}

8 0
3 years ago
Examine the system of equations. y = negative one-fourth x minus 2 x = 4 What is the solution to the system? (–3, –2) (4, –3) (4
Alla [95]

Answer:

Step-by-step explanation:

IF YOU GIVE ME THE CORRECT ANSWER AND HOW YOU GOT THAT ANSWER I WILL GIVE BRAINlYIST

6 0
3 years ago
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