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3 years ago

12

PLEASE HELP!!!!! WILL GIVE BRAINLYIST!!!!!! Explain the three different cross sections that result from cutting a rectangular py

ramid.

2 answers:

Brums [2.3K]3 years ago

8 0

Answer:Now u can give brainliest

Step-by-step explanation:

alexira [117]3 years ago

7 0

1. a rectangle by horizontal bisection, 2. a trangle by vertical bisection, 3. a trapezoidal by diagonal bisection.

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Select the correct answer. A linear function has a y-intercept of -12 and a slope of 3/2. What is the equation of the line? y =

aniked [119]

Answer:

The equation of the line is:

$y\:=\:\frac{3}{2}x\:-12$

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

m is the slope

b is the y-intercept

Given

y-intercept b = -12

slope m = 3/2

now substituting b = -12 and m = 3/2 in the slope-intercept form of line equation

$y = mx+b$

$y\:=\:\frac{3}{2}x\:+\:\left(-12\right)$

$y\:=\:\frac{3}{2}x\:-12$

Therefore, the equation of the line is:

$y\:=\:\frac{3}{2}x\:-12$

8 0

3 years ago

7/8m+9/10-2m-3/5<br> Combine like terms to create an equivalent expression.

stich3 [128]

Answer:

-1.123m+0.3

or in fraction form -9/8m+3/10

Step-by-step explanation:

first you subtract 7/8 from 2

then you subtract again 9/10 from 3/5

4 0

3 years ago

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

3 0

3 years ago

Need some help with multiplying algebraic fractions

Nezavi [6.7K]

Answer:

a=10, b=5, c=2, d=12

Step-by-step explanation:

Multiply each variable together

5*2=10

8*3=24

10 $x^{3}$ $y^{2}$ /24x

the coefficients (numbers) can each be divided by 2

5 $x^{3} y^{2}$ /12x

subtract the "x" exponents together

5 $x^{2} y^{2}$ /12

8 0

3 years ago

Solve for x if the Perimeter = 26<br> 14-2x<br> 2x + 1<br> 3x - 1

sergejj [24]

Answer:

x = 4

Step-by-step explanation:

<em>Perimeter of triangle = sum of all sides</em>

Side 1: 14 - 2x

Side 2: 3x - 1

Side 3: 2x + 1

<em>Perimeter= side 1 + side 2 + side 3</em>

26 = 14 - 2x + 3x - 1 + 2x + 1

26 = 14 - 1 + 1 - 2x + 3x + 2x

26 = 14 + 3x

3x = 12

x = 12/3

x = 4

!!

3 0

3 years ago