The answer is y= 5/4
hope this helps!
Answer: The answer is 183.08
Step-by-step explanation: see the picture attached
Answer:
i think the mistake was in step 1
Step-by-step explanation:
Add the equations,just the way they appear there.
-- Add the top 'x' to the bottom 'x'. Write the sum under the 'x's.
-- Add the '+y' and the '-y'. Write the sum under the 'y's.
-- Add the '2' and the '4'. Write the sum under them, with n " = " sign
before it.
You should now have an equation with only 'x' in it and no 'y'.
You can easily solve that one and find out the value of 'x'.
Once you know the value of 'x', go back to either one of the original
equations, and plug the number-value of 'x' in place of 'x'.
You'll then have an equation with only 'y' in it and no 'x'.
You can easily solve that one and find out the value of 'y'.
Log₄8 + 3 · log₄x
so the easiest way to do this is to note that these logs are separated by an addition symbol--it isn't "log₄8 + 3" times "log₄x"
log₄8
plus
3 · log₄x
for the second log, you can condense it with log properties/rules: the coefficient out front, when you condense it, becomes the exponent for the argument of your log:
3 · log₄x = log₄(x³)
so, having condensed that, your equation reads:
log₄8 + log₄(x³)
you could technically evaluate the first log, but the question wants both of these to become a single logarithm, which means you want to combine them. log properties state that if logs are being added, you can multiply their arguments (for example: logₓab = logₓa + logₓb)
you just want to apply that property to this, so you'll be multiplying your arguments 8 and x³:
log₄(8x³) is the answer, expressed as one logarithm.
