An inchworm (exactly one inch long, of course) is crawling up a yardstick (guess how long that is?). After the rst day, the inch
worm's head (let's just assume that's at the front) is at the 3" mark. After the second day, the inchworm's head is at the 6" mark. After the third day, the inchworm's head is at the 9" mark. Let d equal the number of days the worm has been crawling. (So after the rst day, d = 1.) Let h be the number of inches the head has gone. Let t be the position of the worm's tail.
1 answer:
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The second one is the correct answer.
-x + 7 = x - 5
add x to both sides of the equation
7 = 2x - 5
add 5 to both sides of the equation
12 = 2x
divide 2 from both sides of the equation
6 = x
Answer:
(1/2) qt/(3/4) hr = (1/2)*(4/3) qt/hr = (2/3) qt/hr
The rule for division of fractions is: invert the denominator and multiply.
Answer:
53
Step-by-step explanation:
73 - 20(1)
73 - 20 = 53
Answer: I’m not exactly sure, but I wanna help. So from the Work I’ve done option C is the answer.
Step-by-step explanation: