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Ne4ueva [31]
3 years ago
14

The rate constant for the reaction below is 6.2 x 10−5 mol l−1 s −1. if the initial concentration of a is 0.0500 m, what is its

concentration after 115 s?
Chemistry
1 answer:
snow_tiger [21]3 years ago
8 0

The correct answer is 0.04287 M

It is given that the rate constant of the reaction is 6.2 × 10⁻⁵ mol/L/s

Thus, as the rate of the reaction is in mol/L/s, it is a zero order reaction.  

The initial concentration of a is 0.0500 M, and there is a need to find the concentration of a after 115 seconds. This can be done with the help of the equation:  

[A]o -[A] = kt

[A] = [A]o - kt

= (0.0500 M) - (6.2 × 10⁻⁵) (115 s)

= 0.04287 M


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Explanation:

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Temperature does not affect the radioactive decay

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because Temperature has no factor in radioactivity

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Is food a fuel? Explain your answer. a ?​
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Write the net ionic equation for this precipitation reaction. Include physical states. ( NH 4 ) 2 CO 3 ( aq ) + Ca ( ClO 4 ) 2 (
Bad White [126]

Answer:

The net ionic equation:

Ca^{2+}(aq)+CO_{3}^{2-}(aq) \rightarrow CaCO_{3}(s)

Explanation:

The given chemical reaction is as follows.

(NH_{4})_{2}CO_{3}(aq)+Ca(ClO_{4})_{2}(aq) \rightarrow CaCO_{3}(s)+2NH_{4}ClO_{4}(aq)

The total ionic equation is as follows.

2NH_{4}^{+}(aq)+ CO_{3}^{2-}(aq)+Ca^{2+}(aq)+2ClO_{4}^{-}(aq) \rightarrow CaCO_{3}(s)+2NH_{4}^{+}(aq)+2ClO_{4}^{-}

Similar ions on the both sides of the reaction will be cancelled.

The remaining reaction is

Ca^{2+}(aq)+CO_{3}^{2-}(aq) \rightarrow CaCO_{3}(s)

Therefore, the net ionic reaction is as follows.

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8 0
4 years ago
How many moles are in 43.5 g of sodium hydroxide (NaOH)?
Makovka662 [10]

Answer:

1.09 moles of NaOH

Explanation:

First of all, to calculate moles, you need to find the molar mass of NaOH.

Let us first find the molar mass of NaOH then.

Na = 23.0 amu

O = 16.0

H = 1.0

They are 1 nitrogen atom, 1 oxygen atom, and one hydrogen atom.

So do this.

23.0(1) + 16.0(1) + 1.0(1) = 40 g/mol.

Now use dimensional analysis to show your work

43.5 g of NaOH * 1 mol of NaOH / 40 g/mol of NaOH

The grams cancel out.

43.5 / 40.0 = 1.0875

Use sig figs and round the answer to the nearest hundredths place.

1.0875 = 1.09

So the final answer is 1.09 moles of NaOH

Hope it helped!

3 0
3 years ago
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