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nlexa [21]
3 years ago
9

What is the empirical formula of Fe?

Chemistry
2 answers:
Lera25 [3.4K]3 years ago
7 0

Answer:

The ratio is 1.000 mol of iron to 1.500 mol of oxygen (Fe1O1.5). Finally, multiply the ratio by two to get the smallest possible whole number subscripts while still maintaining the correct iron-to-oxygen ratio: The empirical formula is Fe2O3.

boyakko [2]3 years ago
3 0
The empirical formula is Fe203
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blagie [28]

Malleable, shiny and good conductors
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4 0
3 years ago
Work=? time=5s Power = 40w
antiseptic1488 [7]

Answer:

200 J

Explanation:

Work = Power x time

Work = (40w)(5s)

Work = 200 J

5 0
3 years ago
Identify the combustion reaction. identify the combustion reaction. c(s) + o2(g) → co2(g) 2 h2(g) + o2(g) → 2 h2o(g) c3h8(g) + 5
tester [92]
Combustion reaction occurs when organic compound reacts with oxygen to form CO₂, H₂O and energy
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7 0
3 years ago
The oxidation of Cu₂O(s) to CuO(s) is an exothermic process:
Alex73 [517]

Answer:

w = 7376.6 J

Explanation:

To calculate the work done in the system, we need first to calculate the number of moles of all compounds.

The following expression, that comes from the 1° law of thermodynamic, will help you to get the work:

w = ΔnRT

Where:

Δn: difference in the number of moles between products and reactants

R: constant universal of gases (8.314 J / mol K)

T: Temperature in Kelvin.

As we are doing this reaction in STP, then the Pressure is 1 atm, and temperature is 0 °C or 273 K.

Now, we already have the moles of Cu₂O, let's see, according to the balanced reaction, how many moles we should have of O₂ and CuO.

If 1 mole of O₂ reacts with 2 moles of Cu₂O then 6.5 moles of Cu₂O will be:

moles O₂ = 6.5 moles Cu₂O * (1 mole O₂/2 moles Cu₂O) = 3.25 moles O₂

If 2 moles of Cu₂O produces 4 moles of CuO, then 6.5 moles will be:

moles CuO = 6.5 moles Cu₂O*(4 moles CuO/2 moles Cu₂O) = 13 moles CuO

Now that we have the moles, let's calculate the value of Δn.

Δn = moles product - moles reactants

Δn = 13 - (6.5 + 3.25) = 3.25 moles

Now, we can calculate the work done in the system:

w = 3.25 * (8.314 * 273)

<h2>w = 7376.6 J or 7.3766 kJ</h2>

Hope this helps

8 0
3 years ago
Automobile catalytic converters use a platinum catalyst to reduce air pollution by changing emissions such as carbon monoxide, C
julia-pushkina [17]

Answer: 448 g of O_2 will be required to completely react with 784g moles of CO(g) during this reaction.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} CO=\frac{784g}{28g/mol}=28moles

The balanced chemical equation is:

2CO(g)+O_2(g)\rightarrow 2CO_2(g)  

According to stoichiometry :

2 moles of CO require  = 1 mole of O_2

Thus 28 moles of CO will require=\frac{1}{2}\times 28=14moles  of O_2

Mass of O_2=moles\times {\text {Molar mass}}=14moles\times 32g/mol=448g

Thus 448g of O_2 will be required to completely react with 784g moles of CO(g) during this reaction.

6 0
3 years ago
Read 2 more answers
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