Answer:
Step-by-step explanation:
Ok, so first substitute x for 4 in
"g(x) = 5x + 1", and x for 3 in
"k(x) = 2/x + 2x". Now you got:
g(4) = 5(4) + 1
k(3) = 2/(3) + 2(3)
Now you can solve each individually.
g(4) = 5 × 4 = 20
20 + 1 = 21
g(4) = 21
k(3) = 2 × 3 = 6
6 + 2/3 = 6 2/3
k(3) = 6 2/3
g(4) + k(3) = 21 + 6 2/3 = <u>27 2/3</u>
Hope this helps :)
Answer:
4p+3
Step-by-step explanation:
Because 4 has the variable p next to it, 4 can not be the same as 6 or 3 because they are whole numbers. So the only thing you can do here is 6-3, which is 3.
Answer:
Step-by-step explanation:
A(3,-2) ; B(6,-2)
![AB=\sqrt{(6-3)^{2}+(-2-[-2])^{2}}\\\\ =\sqrt{3^{2}+(-2+2)^{2}}\\\\=\sqrt{9+0}=\sqrt{9}\\\\](https://tex.z-dn.net/?f=AB%3D%5Csqrt%7B%286-3%29%5E%7B2%7D%2B%28-2-%5B-2%5D%29%5E%7B2%7D%7D%5C%5C%5C%5C%20%3D%5Csqrt%7B3%5E%7B2%7D%2B%28-2%2B2%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B9%2B0%7D%3D%5Csqrt%7B9%7D%5C%5C%5C%5C)
AB = 3 units
B(6,-2) ; C(6,5)
![BC=\sqrt{(6-6)^{2}+(5-[-2])^{2}} \\\\=\sqrt{0+(5+2)^{2}}\\\\=\sqrt{(7)^{2}}\\](https://tex.z-dn.net/?f=BC%3D%5Csqrt%7B%286-6%29%5E%7B2%7D%2B%285-%5B-2%5D%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%5Csqrt%7B0%2B%285%2B2%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B%287%29%5E%7B2%7D%7D%5C%5C)
BC = 7 units
Area of rectangle = length * width
= AB * BC
= 3 * 7
= 21 square units
First and last terms of the given equation are perfect squares. They can be written as
(4p^2)^2+ 2.(4p^2).5+(5)^2
It's like identity 1: (a+b)^2=a^2+2ab+b^2
So a=4p^2 and b=5
Therefore it is equal to (4p^2+5)^2
