Consider this system of equations.
2 answers:
We are given two functions.
The point that represents the equation , will also be the intersection of those two lines, meaning we can set the two equations equal to each other and solve for
.
Now that we are given the x value, we can plug this value back into either equation and solve for the y value.
The point of intersection will be .
Hope this helps!
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Let's look at the picture, let's imagine that the gray line is the perimeter fence and that the red OR the blue is the one dividing it. We can see that the blue line is longer than the red one, so it will be advantageous, to have a bigger area, to have the dividing fence the smallest possible.
Let's say then that the width (W) is bigger (or equal) to the length (L), so we have:
The area is W*L, so we have
this function is a parabola facing down, its zeros are 0 and 80, therefore its maximum is when L=40
hence, L=40 and W=(240-120)/2=60
It will be a rectangle, measuring 60x40 and the divinding fence will be 40
Let's say then that the width (W) is bigger (or equal) to the length (L), so we have:
The area is W*L, so we have
this function is a parabola facing down, its zeros are 0 and 80, therefore its maximum is when L=40
hence, L=40 and W=(240-120)/2=60
It will be a rectangle, measuring 60x40 and the divinding fence will be 40