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tia_tia [17]
3 years ago
5

Multiple choice question, do your best !!

Mathematics
1 answer:
jekas [21]3 years ago
3 0
Answer: Choice B) 
(y+5)+y = 6

----------------------------------------------------------------

So what we do is start with x+y = 6. We can replace the 'x' with (y+5). This replacement is possible because x = y+6; ie x and y+6 are the same. Another term for "replace" is "substitute"

This is how we're able to go from x+y = 6 to (y+5)+y = 6
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A carpenter is making a circular tabletop with a circumference of 4.5 yards.
nikitadnepr [17]
The radius of the table top is 206 when rounded to the nearest centimeters
5 0
2 years ago
Given: CB bisects
marin [14]

Answer:

Answer to fourth part is :

Angle ABC= Angle DBC

So for fifth part reason answer is ASA congruency.

Step-by-step explanation:

Here we are given that CB bisects angle ABD and angle ACD.

So we have ,

Angle ABC= Angle DBC

Answer to fourth part is :

Angle ABC= Angle DBC

Now here we have two angles and one side equal in two triangles.

So we can say that ASA congruency fits in the best here.

So for fifth part reason answer is ASA congruency.

4 0
3 years ago
Locate the absolute extrema of the function on the closed interval:<br> y = 3x^(2/3) - 2x, [-1, 1]
Alecsey [184]
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
7 0
3 years ago
How do you Graph y-3=1/3(x+1)
jekas [21]

Answer:

You can find the point of intersection of the line with the y-axis and the  the point of intersection of the line with the x-axis. See the graph attached.

Step-by-step explanation:

Find the intersection with the y-axis. Substitute x=0 into the equation and solve for y:

y-3=\frac{1}{3}(x+1)\\\\y-3=\frac{1}{3}(0+1)\\\\y-3=\frac{1}{3}(1)\\y=\frac{1}{3}+3\\\\y=\frac{10}{3}

y≈3.33

Find the intersection with the x-axis. Substitute y=0 into the equation and solve for x:

y-3=\frac{1}{3}(x+1)

0-3=\frac{1}{3}(x+1)\\(-3)(3)=x+1\\-9-1=x\\x=-10

Now, you know that the line passes through the point (0,3.33) and (-10,0). Now you can graph the function. (Observe the graph attached)

6 0
3 years ago
16x+14y=8 <br> -63x-14y=133
artcher [175]

Answer:

(-3, 4)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination
  • Solving systems of equations by graphing

Step-by-step explanation:

<u>Step 1: Define Systems</u>

16x + 14y = 8

-63x - 14y = 133

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Elimination</em>

  1. Combine 2 equations:                    -47x = 141
  2. Divide -47 on both sides:               x = -3

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                    16x + 14y = 8
  2. Substitute in <em>x</em>:                                     16(-3) + 14y = 8
  3. Evaluate multiplication:                       -48 + 14y = 8
  4. Add 48 on both sides:                        14y = 56
  5. Divide 14 on both sides:                      y = 4

<u>Step 4: Graph Systems</u>

<em>Check the solution set.</em>

4 0
2 years ago
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