The sum of the first 75 terms of the arithmetic sequence that has 10th term as 16 and the 35th term as 66 is 5400.
<h3>How to find the sum of terms using Arithmetic sequence formula</h3>
aₙ = a + (n - 1)d
where
Therefore, let's find a and d
a₁₀ = a + (10 - 1)d
a₃₅ = a + (35 - 1)d
Hence,
16 = a + 9d
66 = a + 34d
25d = 50
d = 50 / 25
d = 2
16 - 9(2) = a
a = 16 - 18
a = -2
Therefore, let's find the sum of 75 terms of the arithmetic sequence
Sₙ = n / 2 (2a + (n - 1)d)
S₇₅ = 75 / 2 (2(-2) + (75 - 1)2)
S₇₅ = 37.5 (-4 + 148)
S₇₅ = 37.5(144)
S₇₅ = 5400
learn more on arithmetic sequence here: brainly.com/question/1687271
Answer:
What figure are you talking about
Answer:
3/5
Step-by-step explanation:
If someone reads the book (Gryphon) by Charles baxter what???
Answer:
Total crackers on the plate are 12
Step-by-step explanation:
Manuel ate crackers = 
His brother ate crackers = 
Crackers left on the plate = 5
We need to find how many crackers were there on the plate.
Let x be the total crackers on the plate
So, we can write the equation
Because 1/3 and 1/4 crackers are eaten and 5 are left so, we subtract 1/3x and 1/4x from x and equal it to 5
So, we get x = 12
Therefore, total crackers on the plate are 12
