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tia_tia [17]
3 years ago
5

Multiple choice question, do your best !!

Mathematics
1 answer:
jekas [21]3 years ago
3 0
Answer: Choice B) 
(y+5)+y = 6

----------------------------------------------------------------

So what we do is start with x+y = 6. We can replace the 'x' with (y+5). This replacement is possible because x = y+6; ie x and y+6 are the same. Another term for "replace" is "substitute"

This is how we're able to go from x+y = 6 to (y+5)+y = 6
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Two terms of an arithmetic sequence are a10=16 and a35=66 find the sum of the first 75 terms
andrew11 [14]

The sum of the first 75 terms of the arithmetic sequence that has 10th term as 16 and the 35th term as 66 is 5400.  

<h3>How to find the sum of terms using Arithmetic sequence formula</h3>

aₙ = a + (n - 1)d

where

  • a = first term
  • d = common difference
  • n = number of terms

Therefore, let's find a and d

a₁₀ = a + (10 - 1)d

a₃₅ = a + (35 - 1)d

Hence,

16 = a + 9d

66 = a + 34d

25d = 50

d = 50 / 25

d = 2

16 - 9(2) = a

a = 16 - 18

a  = -2

Therefore, let's find the sum of 75 terms of the arithmetic sequence

Sₙ = n / 2 (2a + (n - 1)d)

S₇₅ = 75 / 2 (2(-2) + (75 - 1)2)

S₇₅ = 37.5 (-4 + 148)

S₇₅ = 37.5(144)

S₇₅ = 5400

learn more on arithmetic sequence here: brainly.com/question/1687271

4 0
2 years ago
Which is the area of the figure
VladimirAG [237]

Answer:

What figure are you talking about

6 0
3 years ago
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If a student (represented by initials) was chosen at random, find P(HH|C').
valentina_108 [34]

Answer:

3/5

Step-by-step explanation:

6 0
2 years ago
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PLEASE HELP ASAP<br> If Someone read the book "Gryphon" by Charles Baxter please can you help me.
Neko [114]
If someone reads the book (Gryphon) by Charles baxter what???
4 0
3 years ago
PLEASE HELP it should be easy for someone but I can’t do it
-Dominant- [34]

Answer:

Total crackers on the plate are 12

Step-by-step explanation:

Manuel ate crackers = \frac{1}{3}

His brother ate crackers = \frac{1}{4}

Crackers left on the plate = 5

We need to find how many crackers were there on the plate.

Let x be the total crackers on the plate

So, we can write the equation

x-\frac{1}{3}x-\frac{1}{4}x=5

Because 1/3 and 1/4 crackers are eaten and 5 are left so, we subtract 1/3x and 1/4x from x and equal it to 5

\frac{12x-4x-3x}{12}=5\\\frac{12x-7x}{12}=5\\\frac{5x}{12}=5\\x=\frac{5*12}{5}\\x=12

So, we get x = 12

Therefore, total crackers on the plate are 12

8 0
3 years ago
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