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Mandarinka [93]
3 years ago
15

The Earlybird communications satellite hovers over the same point on Earth's equator indefinitely. This is because _____. A. its

orbital period is 24 hours B. it is beyond the main pull of gravity C. it pulls as hard on Earth as Earth pulls on it D. it is kept aloft by ground control E. forces other than Earth's gravity act on it
Physics
2 answers:
Rasek [7]3 years ago
7 0
The Earlybird ... and every TV satellite ... hovers over the same point
on Earth's equator indefinitely because its orbit is continually adjusted
to ...

-- be in the plane of the equator,

-- be as perfectly circular as possible,

-- have a period exactly equal to the Earth's rotation period ...
about 23 hours 56 minutes 4 seconds, not 24 hours. 
Ludmilka [50]3 years ago
3 0
<span>A. its orbital period is 24</span>
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A ball is kicked from a height of 20 meters above the ground. If the initial velocity is 10 m/s, how long is the ball in flight
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A train that has wheels with a diameter of 91.44 cm (36 inches used for 100 ton capacity cars) slows down from 82.5 km/h to 32.5
podryga [215]

Answer:

The answer is below

Explanation:

The initial velocity = u = 82.5 km/h = 22.92 m/s, the final velocity = 32.5 km/h = 9.03 m/s, diameter = 91.55 cm = 0.9144 cm

radius (r) = diameter / 2 = 0.9144 / 2= 0.4572 m

a) Initial angular velocity (\omega_o) = u /r = 22.92 / 0.4572 = 50.13 rad/s, final velocity  (ω) = v / r = 9.03 / 0.4592 = 19.67 rad / s

θ = 95 rev * 2πr = 95 * 2π * 0.4572= 272.9 rad

angular acceleration (α) is:

\omega^2=\omega_o^2+2\alpha \theta\\\\19.67^2-50.13^2=2\alpha(272.9)\\\\19.67^2=50.13^2+2\alpha(272.9)\\\\2\alpha(272.9)=-2126.108\\\\\alpha=-3.89\ rad/s^2\\\\

b)

\omega=\omega_o+\alpha t\\\\19.67=50.13+(-3.89t)\\\\3.89t=50.13-19..67\\\\3.89t=30.46\\\\t=7.83\ s

c) θ = 95 rev * 2πr = 95 * 2π * 0.4572= 272.9 rad

a) When it stops, the final angular velocity is 0. Hence:

\omega^2=\omega_o^2+2\alpha \theta\\\\0=50.13^2+2(-3.89)\theta\\\\2(3.89)\theta=50.13^2\\\\2(3.89)\theta=2513\\\\\theta=323\ rad\\\\revolutions=\frac{\theta}{2\pi r}=\frac{323}{2\pi(0.4572)}  =112.4\ rev

θ = 323 rad

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learn more about Newton's first law of motion here brainly.com/question/10454047

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