The initial speed of the sled at the given height is 4.85 m/s.
<h3>Initial speed of the sled</h3>
Apply the principle of conservation of energy;
K.E = P.E
¹/₂mv² = mgh
v² = 2gh
v = √2gh
where;
- h is the vertical height reached
- g is acceleration due to gravity
v = √(2 x 9.8 x 1.2)
v = 4.85 m/s
Thus, the initial speed of the sled at the given height is 4.85 m/s.
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Answer:
Since their wings and body develop the drag. When there is warm air then they expand their wings. Since,soaring birds and glider pilots have no engine, they always maintain their high speed to lift their weight in air for hours without expending power by convection
Explanation:
Answer:
α = F/(k×m×r)
Explanation:
When the wheel is pulled to turn in a counterclockwise direction, the wheel will have a moment of inertia given by Iw = k×m×r²
Where k = the radius of gyration of the wheel which is a dimensionless quantity less than one.
m = the mass of the wheel
r = the radius of the wheel
First and foremost, we relate the torque (τ) about the axle of the wheel to the force (F) applied on the wheel and we have that τ = r × F
We then relate the torque on the wheel to the angular acceleration (α), we have that τ = Iw × α, where Iw is the moment of inertia of the wheel as explained above
Substituting for torque τ and moment of inertia I into the above equation we have that
r × F = k×m×r² × α
solving for α we have that
α = r × F /(k×m×r²)
Therefore
α = F/(k×m×r)
