Answer:
Option D
Step-by-step explanation:
Properties of a rhombus,
1). Diagonals of a rhombus bisect the opposite angles.
2). Sum of adjacent two angles of a rhombus is 180°.
By property (1),
Diagonal JL will bisect the angles ∠MJK and ∠KLM.
Therefore, m∠KLM = 2(5x + 3)°
Similarly, diagonal KM will bisect the angles ∠JKL and JML.
Therefore, m∠JKL = 2(9x - 11)°
By property (2),
2(9x - 11)° + 2(5x + 3)° = 180°
9x - 11 + 5x + 3 = 90
14x - 8 = 90
14x = 98
x = 7
Since, m∠KLM = 2(5x + 3)°
= 2(5×7 + 3)°
= 76°
Therefore, Option D will be the answer.
(3×1/2) + (6×3/4) + (3×1) + 1 1/4 +1 1/2=11.75
-x(3x-10)=8
-3x^2+10x=8 (DISTRIBUTE)
-3x^2+10x-8=0 (BALANCE TO ZERO)
(-3x+4)(x-2)=0 (FACTOR)
(-x+4/3)(x-2)=0 (SIMPLIFY)
{x=2 OR x= 4/3}
3x-11=x+23
-x -x
2x-11=23
+11 +11
2x=34
x=17
3(17)-11 17+23
=40 =40
explanation ;
you would equal them because they are congruent . & you substitute x for 17 in each equation to find out the degrees of both of the angles :)
