Or btao koi h meri baat samjhne wala <br>h koi ..<br>koi nhi h ..<br>bc

What is the length of segment A (2,1) B (6,6)

stepladder [879]

4.7 because if you plug it in- (2,1) and (6,6) it is 4.7 units

4 0

3 years ago

Read 2 more answers

Two show your work questions

Svet_ta [14]

Answer:

x = 1; y = 1; z = 0

Step-by-step explanation:

First problem:

First equation minus second equation: 3y + 2z = 3 Eq. A

Second equation plus third equation: 2y + 4z = 2 Eq. B

-2 times Eq. A plus Eq. B: -4y = -4

y = 1

Substitute y = 1 in Eq. A: 3 + 2z = 3

2z = 0

z = 0

Substitute z = 0 and y = 1 in original first equation:

-2x + 2 + 0 = 0

-2x = -2

x = 1

Answer: x = 1; y = 1; z = 0

5 0

3 years ago

Order least from greatest -50 44 -3 1.5

sp2606 [1]

Answer:

-50, -31.5, 44 I think

Step-by-step explanation:

8 0

3 years ago

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According to an article in Newsweek, the natural ratio of girls to boys is 100:105. In China, the birth ratio is 100:114 (46.7%

mojhsa [17]

Answer:

$z=\frac{0.42 -0.467}{\sqrt{\frac{0.467(1-0.467)}{150}}}=-1.154$

$p_v =2*P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of girls born is not significantly different from 0.467

Step-by-step explanation:

Data given and notation

n=150 represent the random sample taken

X=63 represent the number of girls born

$\hat p=\frac{63}{150}=0.42$ estimated proportion of girls born

$p_o=0.467$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion if girls is 0.467.:

Null hypothesis: $p=0.467$

Alternative hypothesis: $p \neq 0.467$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.42 -0.467}{\sqrt{\frac{0.467(1-0.467)}{150}}}=-1.154$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of girls born is not significantly different from 0.467

3 0

2 years ago

7.2 ÷ 0.09 = 7.2/0.09 = ________ Write your quotient as a whole number.

const2013 [10]

Answer:

80

Step-by-step explanation:

5 0

2 years ago

Or btao koi h meri baat samjhne wala h koi ..koi nhi h ..bc​

Or btao koi h meri baat samjhne wala h koi ..koi nhi h ..bc