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3 years ago

A rectangular prism has a base that is 6 m by 3.5 m in the prism is 9 m high what is the surface area of the prism

Mathematics

1 answer:

brilliants [131]3 years ago

5 0

Answer:

213 meters squared

Step-by-step explanation:

The surface area of a rectangular prism is found using the formula A=2(wl+hl+hw). Here substitute l = 6, w = 3.5 and h = 9.

A = 2((3.5*6) + (9*6) + (3.5*9))

A = 2(21 + 54 + 31.5)

A = 2(106.5)

A = 213

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18x + 9y use the distributive property to write an equivalent expression

kirza4 [7]

Hey there!
It looks like you have another factoring question!
Using our definition of the distributive property:
a(b+c) = ab+ac
We need to factor our or greatest common multiple, which here is 9.
9 times 2x = 18x and 9 times y = 9y
We have:
9(2x + y)
Once again, using the distributive property, multiply it out and you'll get 18x and 9y.
Hope this helps!

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2 years ago

The volume of a sphere is 267.95 m2. To the nearest meter, what is the radius of the sphere? Use

Novosadov [1.4K]

Answer:

Step-by-step explanation:

v=4/3 pi r^3
substitute 267.95=4/3×3.14×r^3
267.95= 12.56r^3/3
multiply by the reciprocal on both sides 64=r^3
find the cuberoot on both sides to remove the cube hence 4=r

3 0

3 years ago

yesterday Stephanie spent $38.72 on new shoes and $23.19 on computer software when she was finished she had $38.18 how much mone

NikAS [45]

Answer: She had $61.91,

Step-by-step explanation:

6 0

2 years ago

Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that

Maksim231197 [3]

Complete Question

The Brown's Ferry incident of 1975 focused national attention on the ever-present danger of fires breaking out in nuclear power plants. The Nuclear Regulatory Commission has estimated that with present technology there will be on average, one fire for every 10 years for a reactor. Suppose that a certain state has two reactors on line in 2020 and they behave independently of one another. Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that by 2030 at least two fires will have occurred at these reactors?

Answer:

The value is $P(x_1 + x_2 \ge 2 )= 0.5940$

Step-by-step explanation:

From the question we are told that

The rate at which fire breaks out every 10 years is $\lambda = 1$

Generally the probability distribution function for Poisson distribution is mathematically represented as

$P(x) = \frac{\lambda^x}{ k! } * e^{-\lambda}$

Here x represent the number of state which is 2 i.e $x_1 \ \ and \ \ x_2$

Generally the probability that by 2030 at least two fires will have occurred at these reactors is mathematically represented as

$P(x_1 + x_2 \ge 2 ) = 1 - P(x_1 + x_2 \le 1 )$

=> $P(x_1 + x_2 \ge 2 ) = 1 - [P(x_1 + x_2 = 0 ) + P( x_1 + x_2 = 1 )]$

=> $P(x_1 + x_2 \ge 2 ) = 1 - [ P(x_1 = 0 , x_2 = 0 ) + P( x_1 = 0 , x_2 = 1 ) + P(x_1 , x_2 = 0)]$

=> $P(x_1 + x_2 \ge 2 ) = 1 - P(x_1 = 0)P(x_2 = 0 ) + P( x_1 = 0 ) P( x_2 = 1 )+ P(x_1 = 1 )P(x_2 = 0)$

=> $P(x_1 + x_2 \ge 2 ) = 1 - \{ [ \frac{1^0}{ 0! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]] )+ ( [ \frac{1^1}{1! } * e^{-1}] * [[ \frac{1^1}{ 1! } * e^{-1}]] ) + ( [ \frac{1^1}{ 1! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]]) \}$

=> $P(x_1 + x_2 \ge 2 )= 1- [[0.3678 * 0.3679] + [0.3678 * 0.3679] + [0.3678 * 0.3679] ]$

$P(x_1 + x_2 \ge 2 )= 0.5940$

3 0

3 years ago

If y=5x-7, determine the value of y when x=-3

alexdok [17]

Answer:-22

Step-by-step explanation:

5 times -3 equals -15, and the combine it with -7 to get -22

5 0

2 years ago

Read 2 more answers