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schepotkina [342]
3 years ago
8

What is the inverse of the function g(x)=-\dfrac{2}{3}x-5g(x)=− 3 2 ​ x−5g, left parenthesis, x, right parenthesis, equals, minu

s, start fraction, 2, divided by, 3, end fraction, x, minus, 5?
Mathematics
1 answer:
Semenov [28]3 years ago
8 0

Answer:

g^{-1}(x)=-\frac{3}{2}x-\frac{15}{2}

Step-by-step explanation:

Given function,

g(x) = -\frac{2}{3}x-5

Step 1 : Replace g(x) by y:

y = -\frac{2}{3}x-5

Step 2 : Swap x and y:

x = -\frac{2}{3}y-5

Step 3 : Solve the equation for y ( isolate y in the left side ):

x +\frac{2}{3}y=-5

     \frac{2}{3}y=-5-x

      y=\frac{3}{2}(-5-x)

      y=-\frac{15}{2}-\frac{3}{2}x

      y=-\frac{3}{2}x-\frac{15}{2}

Step 4: Replace y by g^{-1}(x):

g^{-1}(x)=-\frac{3}{2}x-\frac{15}{2}

Hence, the inverse of the function g(x) is g^{-1}(x)=-\frac{3}{2}x-\frac{15}{2}.

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