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Archy [21]
3 years ago
8

There are 20 students on the school's student council. A special homecoming dance committee will be formed by randomly selecting

6 students from student council.
How many possible committees can be formed?
Mathematics
1 answer:
inysia [295]3 years ago
6 0
3, because 6x3=18 and there'd be two people left over. And you need six people to form 1 committe and there's only two people left over so those two people just wouldn't be able to be part of anything.

Hope, this helps. :D

You might be interested in
A rectangle has a length at least four more than five times the width. if the perimeter is at least 44 units. find the least pos
Eva8 [605]
The answer is 3 and you get that by using the formula for the area of rectangle, p=2L+2W
44=2(4+5w) + 2w
44=8+10w + 2w
44=8+12w
44-8=8+12w-8
36=12w
36/12=12w/12
3=w
If you plug 3 back into the original formula then you see that it is equal to the perimeter of 44
P=2(4+5w) + 2w
P=2(4+5•3) + 2(3)
P=2(19) +6
P=38+6
P=44
8 0
3 years ago
Normally a new cell phone costs $500 you only have 450 to spend what happened what percent do you need the phone to be discounte
alina1380 [7]
450/500  how much you have to how much it costs
this equals to 90 % of the complete cost

100%-90%=10%

you need a 10 % discount

hope this helps

5 0
4 years ago
Monica receives a flat rate of $25 and an hourly rate of $15 when she works. Which of the following equations represents the tot
shutvik [7]

Answer

d=25+15x I think

                   

5 0
3 years ago
Assume the sample below is a perfectly random sample of students at a school. How much greater is the mean of the
igor_vitrenko [27]

Answer:

0.75

Step-by-step explanation:

The table is not well presented (See Attachment)

There are at least two approaches to this question

Method 1:  

Steps

1. Calculate the mean of reported heights

Mean of reported heights = (61+68+57.5+48.5+75+65+80+68+69+63)/10

Mean of reported heights = 655/10

Mean of reported heights = 65.5

2. Calculate the mean of measured heights

Mean of measured heights = (62 + 68 + 56.5 + 47 + 72 + 65 + 78 + 67 + 69.5 + 62.5)/10

Mean of measured heights = 647.5/10

Mean of measured heights = 64.75

3. Get their difference

Difference = Mean of reported heights - Mean of measured heights

Difference = 65.5 - 64.75

Difference = 0,75

Method 2: Calculate the mean of their difference

Mean of difference = Sum of difference / Number of observations

Mean of difference = (-1 + 0 + 1 + 1.5 + 3 + 0 + 2 + 1 – 0.5 + 0.5)/10

Mean of difference = 7.5/10

Mean of difference = 0.75

Note that in both cases, the result is 0,75.

Hence, the reported heights at the school is 0.75 greater than the actual measured height

3 0
3 years ago
Read 2 more answers
I need help bad! I need help with the last question!
MAVERICK [17]
Use the fact that 1 axe head = 3.20 trade value.
Let N denote number of axe heads needed to trade for a trade gun.
3.20×N=120.00
》 N=120/3.2 which will give number of axe heads needed. Round to the nearest ones place if you must.
5 0
3 years ago
Read 2 more answers
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