Answer:
(A) There should have been 5 outcomes of HT
(B) The experimental probability is greater than the theoretical probability of HT.
Step-by-step explanation:
Given
-- Sample Space
--- Sample Size
Solving (a); theoretical outcome of HT in 20 tosses
First, calculate the theoretical probability of HT


Multiply this by the number of tosses


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Solving (b); experimental probability of HT
Here, we make use of the table


---- Experimental Probability
In (a), the theoretical probability is:

---- Experimental Probability
By comparison;

Answer:
t = 20 + q (minutes)
Step-by-step explanation:
The meeting consists of speaking and Question & Answer (Q&A) sessions.
Speaking session = 20 minutes
Q&A session = q minutes
Total number of minutes spent for the two sessions = 20 + q (minutes)
But total number of minutes meeting lasted = t minutes.
Therefore, t = 20 + q (because they both represent the total number of minutes the meeting lasted)
Answer:
It is A and I am positive its A
Step-by-step explanation:
9514 1404 393
Answer:
Step-by-step explanation:
The thrust of the question is to make sure you understand that increasing the y-coordinate of a point will move the point upward, and decreasing it will move the point downward.
That is adding a positive value "k" to x^2 will move the point (x, x^2) to the point (x, x^2+k), which will be above the previous point by k units.
If k is subtracted, instead of added, then the point will be moved downward.
The blanks are supposed to be filled with <u> positive </u>, and <u> negative </u>.
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<em>Comment on the question</em>
The wording of the statement you're completing is a bit odd. If k is negative (-2, for example), this statement is saying the graph is translated down -2 units. It is not. It is translated down |-2| = 2 units. The direction of translation depends on the sign of k. The amount of translation depends on the magnitude of k.
If you thoroughly understand (x, y) coordinates and how they are plotted on a graph, it should be no mystery that changing the y-coordinate will change the vertical position of the graph.
Area of the triangle = (1/2)*base*height
For right triangle base and height can be legs.
We have one leg = 5 ft. (Lets think it is a base.)
We need to find the other leg.
We are going to use Pythagorean theorem.
5² + b²=13²
b²=144
b=12 (It is going to be our height.)
Area of the triangle = (1/2)*5*12= 30 ft²
Area of the triangle = 30 ft²