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babunello [35]
3 years ago
9

Solve for the missing side multiple choice please answer

Mathematics
2 answers:
SpyIntel [72]3 years ago
5 0

Answer:

The answer is option 3 .

Step-by-step explanation:

In order to find x, you have to use Pythogaras Theorem, c² = a² + b² :

{c}^{2}  =  {a}^{2}  +  {b}^{2}

Let a = 9,

Let b = 7,

Let c = x

{x}^{2}  =  {9}^{2}  +  {7}^{2}

{x}^{2}  = 81 + 49

{x}^{2}  = 130

x =  \sqrt{130}

Alexus [3.1K]3 years ago
3 0

Answer:

x= square root of 130

Step-by-step explanation:

a^2+b^2=c^2

a=7 b=9 c=x

49+81=x^2

130=x^2

square root of 130=x

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Pls help me with 4 , 5 , and 6 and show me how you did it i will mark brainlist !!
LuckyWell [14K]

Answer:

2 on top and bottom of 4   5 is 3 on top and bottom      and lastly 6 is 8 on top and bottom.

Step-by-step explanation:

all you have to do is divide the two bottom numbers on each problem and the answer to the problem will be the same on top and bottom

3 0
3 years ago
Help on questions 11 and 15 Add and simplify if possible
Svetllana [295]
\frac{16+x}{x^3}+\frac{7-4x}{x^3}=\frac{16+x+7-4x}{x^3}=\frac{23-3x}{x^3}\\\\======================================\\\\\frac{5}{t-1}+\frac{3}{t}=\frac{5t}{t(t-1)}+\frac{3(t-1)}{t(t-1)}=\frac{5t+3t-3}{t^2-t}=\frac{8t-3}{t^2-t}
7 0
3 years ago
Read 2 more answers
Help
kykrilka [37]

Let n =  the hours elapsed when the two trains are 660 miles apart.


Let the first train travel east and the second train travel west.

The distance traveled by the first train is

x = (50 mi/h)*(n h) = 50n mi


The distance traveled by the second train is

y = (60 mi/h)*(n h) = 60n h


The distance between the two trains after n hours is

x + y = 50 n + 60n = 110n mi


Because this distance is 660 miles, therefore

110n = 660

n = 6 hours


Answer: 6 hours


I hope this helps. Sorry it took so long

3 0
3 years ago
What is one plus one
Nadya [2.5K]

Answer:

most likely 5

Step-by-step explanation:

3 0
3 years ago
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A) Graph the function and label all zeros. Be sure to label the axis and what you are incrementing by.
Liono4ka [1.6K]

9514 1404 393

Answer:

  • graph is shown below
  • absolute max and min do not exist
  • local max: 0 at x=0
  • local min: -500/27 ≈ -18.519 at x=10/3

Step-by-step explanation:

The function is odd degree so has no absolute maximum or minimum. It factors as ...

  g(x) = x^2(x -5)

so has zeros at x=0 (multiplicity 2, meaning this is a local maximum*) and x=5.

Differentiating, we find the derivative of g(x) is zero at x = 0 and x = 10/3.

  g'(x) = 3x^2 -10x = x(3x -10)   ⇒   x=0 and x=10/3 are critical points

The value of g(10/3) is a local minimum. That value is ...

  g(10/3) = (10/3)^2((10-15)/3) = -500/27 ≈ -18.519

__

The local maximum is (0, 0); the local minimum is (10/3, -500/27). The graph is shown below.

_____

* When a root has even multiplicity, the graph does not cross the x-axis. That means the root corresponds to a local extremum. Since this is the left-most root of an odd-degree function with a positive leading coefficient, it is a local <em>maximum</em>. (The function is <em>increasing</em> left of the left-most turning point.)

7 0
2 years ago
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