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Nastasia [14]
3 years ago
7

The potential energy of a 0.15 kg pendulum is 15 J at the tops of its swing, what is its kinetic energy at the bottom?

Physics
1 answer:
Jlenok [28]3 years ago
7 0
C) 15 J because it cannot gain energy or lose mass
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In the heat equation, what does c represent?
padilas [110]

Answer:

specific heat of the substance

4 0
3 years ago
The magnet below is cut in half. what will be the result?
garik1379 [7]

Answer:

C.

Explanation:

This is what we call a permanent magnet. By the  way, the magnetic phenomena were first observed about 2500 years ago near the ancient city of Magnesia, what is today Manisa, located in western Turkey, when people saw fragments of magnetized iron. So what happens if you cut a magnet in half? Well, a magnet has two ends, the first one is called a north pole or N pole while the  other end is a south pole or S pole, so if you break a bar magnet, each piece  has a north and south pole, no matter the size of each new bar although the smaller the  piece, the weaker its magnetism. This is true because unlike electric charges, you always find magnetic poles  in pairs, that is, ¡they can't be isolated! The option is C. because in the great bar the north pole is to the left while the south pole is to right.

4 0
3 years ago
A window has a glass surface of 2907 cm2 and a thickness of 5.6 mm. Find the rate of energy transfer by conduction through this
butalik [34]

Answer:

2.30714 W

-16.38071 W

Explanation:

k = Heat conduction coefficient = 0.8 W/(m·°C)

A = Area = 2907 cm²

l = Thickness = 5.6 mm

T_2 = Outside temperature

T_1 = Inside temperature

Rate of heat transfer is given by

Q=\frac{kA(T_2-T_1)}{l}\\\Rightarrow Q=\frac{0.8\times 2907\times 10^{-6}\times (81-71)\times \frac{5}{9}}{5.6\times 10^{-3}}\\\Rightarrow Q=2.30714\ W

The rate of energy transfer is 2.30714 W

Q=\frac{kA(T_2-T_1)}{l}\\\Rightarrow Q=\frac{0.8\times 2907\times 10^{-6}\times (0-71)\times \frac{5}{9}}{5.6\times 10^{-3}}\\\Rightarrow Q=-16.38071\ W

The rate of energy transfer is -16.38071 W

7 0
3 years ago
A 21 kg chair initially at rest on a horizontal floor requires a 175 N horizontal force to set it in motion. Once the chair is i
Alika [10]

Answer:\mu =0.85

Explanation:

Given

mass of chair m=21 kg

Force required to set chair in motion is 175 N

Once the chair is in motion 137 N is require to move it with constant velocity

i.e. 175 N is the amount of force needed to just overcome static friction and 137 is the kinetic friction force

thus

f_s(static\ friction)=\mu \cdot N

where \muis the coefficient of static friction and N is Normal reaction

N=mg

f_s=\mu mg

\mu mg=175

\mu =\frac{175}{21\times 9.8}

\mu =0.85

8 0
3 years ago
For a freely falling object dropped from
vlada-n [284]

If you stay on or near the surface of Earth, then the acceleration due to gravity

is constant.  It's 9.807 meters per second squared. (rounded)

7 0
3 years ago
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