A 50kg car is moving at a velocity of 4 m/s. After a collision, the car is moving at a velocity of 5m/s.
1 answer:
You might be interested in
Answer:
and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..
Explanation:
Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = age of sample
= let initial amount of the reactant
a = amount left after decay process
We have :
t = 95 s
Half life is given by for first order kinetics::
and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..
Answer:
9.73 x 10⁻¹⁰ m
Explanation:
According to Heisenberg uncertainty principle
Uncertainty in position x uncertainty in momentum ≥ h / 4π
Δ X x Δp ≥ h / 4π
Δp = mΔV
ΔV = Uncertainty in velocity
= 2 x 10⁻⁶ x 3 / 100
= 6 x 10⁻⁸
mass m = 0.9 x 10⁻¹⁵ x 10⁻³ kg
m = 9 x 10⁻¹⁹
Δp = mΔV
= 9 x 10⁻¹⁹ x 6 x 10⁻⁸
= 54 x 10⁻²⁷
Δ X x Δp ≥ h / 4π
Δ X x 54 x 10⁻²⁷ ≥ h / 4π
Δ X = h / 4π x 1 / 54 x 10⁻²⁷
=
= 9.73 x 10⁻¹⁰ m