(3x^2y)(7x^2y)(-2x^2y)

2 answers:

3 0

$(3x^2y)(7x^2y)(-2x^2y)=\\ \\=3\cdot 7\cdot (-2)\cdot x^2\cdot x^2\cdot x^2 \cdot y \cdot y \cdot y=\\ \\= -42\cdot x^{2+2+2}\cdot y^{1+1+1}=\\ \\=-42x^6y^3$

UNO [17]3 years ago

3 0

(3x^2y)(7x^2y)(-2x^2y)

=-42x^2+ ^2x^2yyy

=-42x^6y^3

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