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natulia [17]
3 years ago
11

In quadrilateral ABCD, /, /, and /. Find the measure of /.

Mathematics
1 answer:
zvonat [6]3 years ago
4 0
'a' i think sorry if wrong

You might be interested in
2) The sum of three consecutive multiples of 6 is 162. Find the multiples.
Andru [333]

Answer:

48, 54 and 60

Step-by-step explanation:

Let the three multiples be 6x, 6(x+1) and 6(x+2) respectively.

6x+6(x+1)+6(x+2)=162

6x+6x+6+6x+12=162

18x=144

x=8

Therefore, the three multiples are 6(8), 6(8+1) and 6(8+2)

i.e. 48, 54 and 60

7 0
2 years ago
2. The sum of three consecutive integers is 48. What are the three integers?
Natasha2012 [34]

Answer: 15, 16, 17

Step-by-step explanation: you have to divide 48 by 3 when you do this then you get the center number in this case 16 so all you have to do now is add the lower number (15) and the higher number (17) and add and they will equal 48

hope this helps please mark brainliest if it helps

5 0
2 years ago
14.4% of a voters in middleville voted for rocky rufus for mayor. if 2500 people voted, how many votes did rocky get?
il63 [147K]

Answer:

360 votes

Step-by-step explanation:

Move the decimal to the left 2 times and you'll get .144. Multiply that by 2500, and you have your answer.

3 0
3 years ago
How can I use models to help me divide??
Ivan
You can use models to help you divide by making the number of models as your divisor. For example let's say I am dividing 8 ÷ 2. So you would make 8 circles (doesn't have to be circle it can be whatever like squares) and then make groups of 2 until you run out of circles. Then how many groups there are is your answer. 8÷2=4. Hope I helped!
4 0
2 years ago
What is the area of the sector ?​
worty [1.4K]

They forget to say "not to scale".  I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first.  By the Law of Cosines

x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ

We have an isosceles triangle formed by two radii of 9 cm and x=PQ.  By the Law of Cosines again,

x^2 = 9^2 + 9^2 - 2(9)(9) \cos B

x^2 = 162 - 162 \cos B

\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}

\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}

B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)

The area of the circle is the fraction given by the angle,

A = \dfrac{B}{360^\circ} \pi r ^2

A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2

A\approx 24.7474332960707

Answer: 24.7 sq cm

8 0
2 years ago
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