First, let's calculate the mean and the mean absolute deviation of the first bowler.
FIRST BOWLER: <span>8,5,5,6,8,7,4,7,6 Mean = (Sum of all data)/(Number of data points) = (8+5+5+6+8+7+4+7+6)/9 <em>Mean = 6.222</em> Mean absolute deviation or MAD = [</span>∑(|Data Point - Mean|]/Number of Data Points MAD = [|8 - 6.222| + |5 - 6.222| + |5 - 6.222| + |6 - 6.222| + |8 - 6.222| + |7 - 6.222| + |4 - 6.222| + |7 - 6.222| + |6 - 6.222|]/9 <em>MAD = 1.136</em>
SECOND BOWLER: <span>10,6,8,8,5,5,6,8,9 </span>Mean = (Sum of all data)/(Number of data points) = (<span>10+6+8+8+5+5+6+8+9</span>)/9 <em>Mean = 7.222</em> Mean absolute deviation or MAD = [∑(|Data Point - Mean|]/Number of Data Points MAD = [|10 - 7.222| + |6 - 7.222| + |8 - 7.222| + |8 - 7.222| + |5 - 7.222| + |5 - 7.222| + |6 - 7.222| + |8 - 7.222| + |9 - 7.222|]/9 <em>MAD = 1.531 </em> The mean absolute deviation represents the average distance of each data to the mean. Thus, the lesser the value of the MAD is, the more consistent is the data to the mean. <em>B</em><em>etween the two, the first bowler is more consistent.</em>
We need to calculate the slope of each of the given sets of points until we find the set associated with a slope of 3/4:
F. (0,5) and (-4,2) As we go from (-4, 2) to (0,5), x increases by 4 and y increases by 3, so the slope is m = rise / run = 3/4. This is the line with slope 3/4.
