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shusha [124]
3 years ago
8

How do I solve... a for this equation? What steps should I take to solve it? 2B(F+a)=H

Mathematics
1 answer:
den301095 [7]3 years ago
7 0
You can’t do anything with the parenthesis yet. So divide both sides by 2B. It cancels on the left side and it is now on the right side in the form:
(F + a) = H/2B

Now all you have to do is subtract F from both sides to get:
a = H/2B - F
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Solve for ppp. 16-3p=\dfrac23p+516−3p= 3 2 ​ p+516, minus, 3, p, equals, start fraction, 2, divided by, 3, end fraction, p, plus
Ksivusya [100]

Given:

The given equation is:

16-3p=\dfrac{2}{3}p+5

To find:

The value of p.

Solution:

We have,

16-3p=\dfrac{2}{3}p+5

Multiply both sides by 3.

3(16-3p)=3\left(\dfrac{2}{3}p+5\right)

48-9p=2p+15

Isolating the variable terms, we get

48-15=2p+9p

33=11p

Divide both sides by 11, we get

\dfrac{33}{11}=p

3=p

Therefore, the required solution is p=3.

7 0
2 years ago
i have to make an expression that has a value of 10 out of the numbers 5,2,1,1 and the format it has to go in is like ( - )+( x
soldi70 [24.7K]

Answer:

(1-1)+(5×2)

hope this helps you

6 0
2 years ago
60/61177.0 Round to the nearest tenth
weeeeeb [17]

60 / 61177  =  0.00098...

The next larger tenth is  0.1 .
The next smaller tenth is  0.0 .

0.00098...  is closer to  0.0  then it is to  0.1 .

60/61177  rounded to nearest tenth  =  zero.

5 0
3 years ago
Evaluate -(2^6)(2^3)
valina [46]

Answer:

- (2^9)

Step-by-step explanation:

-(2^6)(2^3)

We know a^b * a^c = a^( b+c)

- ( 2 ^ (6+3))

- (2^9)

7 0
3 years ago
I need help with question 5 and its solve by subtitution
Bingel [31]
Y = 3x + 15
y = 2x + 8

3x + 15 = 2x + 8
-2x -2x
——————-
x + 15 = 8
-15 -15
—————-
x = -7
4 0
3 years ago
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