I hope this helps you
How do I solve... a for this equation? What steps should I take to solve it? 2B(F+a)=H
1 answer:
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let us first plug the values of r and s here
r=14 and s=8
Now here we can cancel 14 and 7 as 7*2 =14 , also we can cancel 8 and 8 as 8*1 is 8, so our simplified new form is:
Now we can multiply 3*2 and 5*1
3*2 =6
5*1=5
Next we add the two numbers
6+5 =11
So this is how we get the answer 11
Check the picture below.
now, since we know what "f" is, let us use the CNT triangle with the small COR one.
