<h3>
Answer: (3, 0)</h3>
=================================================
Explanation:
Let's isolate x in the first equation.
x-2y = 3
x = 3+2y
Then we'll plug this into the second equation
Afterwards, solve for y.
2x + 4y = 6
2(3+2y)+4y = 6
6+4y+4y = 6
8y+6 = 6
8y = 6-6
8y = 0
y = 0/8
y = 0
Use this to find x.
x = 3+2y
x = 3+2(0)
x = 3
The solution is therefore (x,y) = (3, 0)
If you were to graph both lines, then they would intersect at the location (3,0).
-----------------------------
Checking the answer:
Plug x = 3 and y = 0 into the first equation.
x-2y = 3
3-2(0) = 3
3 - 0 = 3
3 = 3 that works
Repeat for the other equation
2x+4y = 6
2(3) + 4(0) = 6
6 + 0 = 6
6 = 6 that works as well
Both equations are true when (x,y) = (3,0).
The solution is confirmed.
The value of 
is 31
Explanation:
The given expression is 
We need to determine the value of
The value of can be determined by substituting 
in the expression
Thus, we have,
Adding the terms, we have,
Thus, the value is 31.
Therefore, the simplified value of the expression by substituting in the expression is 31.
area = width * length
or
A = W * L
55 = W * (W+6)
solve for width:
0 = W^2 + 6W - 55
this is a quadratic and has two solutions -11 and 5
a length can only be non-negative so discard -11.
width W = 5 miles
now the length is 5+6 = 11 miles
Answer:
subtract the area of the rectangle from the area of the triangle
Answer:
Part A number 2 (see work below)
<em>*please give me brainliest lol*</em>
Step-by-step explanation:
(8r^3 + 2r^2 + 1) - (7 - 7r^3 + 3r^2)
<em>after factoring out the negative, you'll have:</em>
8r^3 + 2r^2 + 1 -7 + 7r^3 - 3r^2
<em>now we combine like terms, and your answer is:</em>
15r^3 - r^2 - 6
<u>hope this helps!</u>
