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Rama09 [41]
3 years ago
15

A frog leaps 24 inches. The highest point in the jump is 6 inches. Assume the frog starts at (0,0). What quadratic function mode

ls the path of the jump?
Mathematics
1 answer:
Ivanshal [37]3 years ago
5 0
The path is in the shape of a parabola, the horizontal length is 24, so the middle point is at x=12, the symmetry line is x=12, the highest point (the vertex) is at (12,6)
the equation in vertex form is y=a(x-12)²+6
next, find a by using either one of the two points, the starting point (0,0) or the end point (0,24). obviously (0,0) is easier to calculate:
0=a(0-12)² +6
a=-1/24
so the quadratic equation is y=-\frac{1}{24} (x-12)^2+6
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Expand and Simplify 3(4x + 1 ) -2(3x-4)
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Answer:

<h3>\boxed{ \bold{ 6x + 11}}</h3>

Step-by-step explanation:

\mathsf{3(4x + 1) - 2(3x - 4)}

Distribute 3 through the parentheses

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Theequationforlinegcanbewrittenas y = –9 4 x − 1 . Line h , whichisperpendiculartoline g , includesthepoint (10, 4) . What isthe
KATRIN_1 [288]

Answer:

y-4 = 4/9(x-10)

Step-by-step explanation:

Given the equation of the line g to be y = -9/4 x - 1.

To find the equation of a line h perpendicular to this line, the following steps must be taken;

First find the slope of the known line g

The standard equation of a line is y = mx+c where

m is the slope

c is the intercept

Comparing this equation with the given equation y = -9/4 x -1, it can be seen that the slope of the line g is -9/4

Next is to find the slope of the line h

Since the line g is perpendicular to h, then the product of their slope will be -1 i.e mh*mg = -1

mh = -1.mg

mh = -1/(-9/4)

mh = -1*-4/9

mh = 4/9

Hence the slope of the line h is 4/9

Find the intercept of line h

To get this, you will substitute the slope m and the point into the equation y = mx+c

m = 4/9

(x,y) = (10,4)

4 = 4/9(10) + c

4 = 40/9 + c

c = 4-40/9

c = (36-40)/9

c = -4/9

Hence the intercept of the line h is -4/9

Finally, find the equation of the line h in slope-intercept form

The slope-intercept form of a line is expressed as y = mx+c

y-y0 = m(x-x0)

Given

m = -4/9

x0 = 10

y0 = 4

Substitute:

y-4 = 4/9(x-10)

Hence the equation in slope-intercept form is y-4 = 4/9(x-10)

7 0
3 years ago
Help me please!!!!!!!!!!!!!
AnnZ [28]

For this case the vertex of the parabola is the point at which the parabola presents a minimum.

The parabola presents a minimum in this case, because the parabola opens upwards.

The vertex is then a minimum.

The vertex of the function is located in the following ordered pair:

(x, y) = (1, -1)

Answer:

(x, y) = (1, -1)

minimum

Option A

8 0
3 years ago
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