Kinetic Energy - What does it depend on?

Give the number of protons (p), electrons (e), and neutrons (n) in one atom of nickel-62. A) 28 p, 28 e, 28 n B) 28 p, 28 e, 34

Reika [66]

<h2>Option B is the correct answer.</h2>

Explanation:

We need to find number of protons, electrons and neutrons in ⁶²Ni

Mass number is 62.

That is

Number of proton + Number of neutron = 62

We know that number of proton = 28 for nickel

So

28 + Number of neutron = 62

Number of neutron = 62 - 28 = 34

We also know

Number of protons = Number of electrons

Number of electrons = 28

Option B is the correct answer.

3 0

3 years ago

For fully developed laminar pipe flow in a circular pipe, the velocity profile is u(r) = 2(1-r2 /R2 ) in m/s, where R is the inn

sdas [7]

Answer:

a) $v_{max} = 2\ \textup{m/s}$

b) $v_{avg} = 1\ \textup{m/s}$

c) Q = 1.256 × 10⁻³ m³/s

Explanation:

Given:

The velocity profile as:

$u(r) = 2(1-\frac{r^2}{R^2} )$

Now, the maximum velocity of the flow is obtained at the center of the pipe

i.e r = 0

thus,

$v_{max}=u(0) = 2(1-\frac{0^2}{R^2} )$

or

$v_{max} = 2\ \textup{m/s}$

Now,

$v_{avg} = \frac{v_{max}}{2}\ \textup{m/s}$

or

$v_{avg} = \frac{2}}{2}\ \textup{m/s}$

or

$v_{avg} = 1\ \textup{m/s}$

Now, the flow rate is given as:

Q = Area of cross-section of pipe × $v_{avg}$

or

Q = $\frac{\pi D^2}{4}\times v_{avg}$

or

Q = $\frac{\pi 0.04^2}{4}\times 1$

or

Q = 1.256 × 10⁻³ m³/s

7 0

3 years ago

Car 1 of mass 1,715kg is sitting at an intersection. Car 2 of mass 2,780kg read ends Car 1, knocking it forward at 8 m/s. If Car

SVEN [57.7K]

Answer:8 miles

Explanation:

8 0

3 years ago

1. In what year did India (our second most populous country) begin to produce more energy than Spain?

choli [55]

Answers:

<h2>1) Sometime in 2014 </h2>

As we can see in the graph in 2014 there is an intersection between the lines that represent the wind energy production of Spain and India, then the production of India is increased, while that of Spain remains constant.

<h2>2) Germany </h2>

As we can see in the graph in 2000 Germany was the number 1 producer of gigawatts of wind energy. In addition it is observed a rapid growth and increase in production compared to the other countries.

<h2>3) In 2006, America was producing over 10 GW and began a steep climb in wind energy production.</h2>

In 1997, America began with a constant and very small energy production, which was growing gradually until 2006, when its rapid growth in production began to exceed the other countries shown in the graph.

<h2>4) Years</h2>

When a function is plotted, generally the independent variable, whose value is previously set, is represented on the X axis.

In this sense, the variable found on the X axis of this graph is Years.

<h2>5) Wind Energy Capacity </h2>

When a function is plotted, generally the dependent variable (which is generated from the independent variable) is represented on the Y axis.

In this sense, the variable found on the Y axis of this graph is Wind Energy Capacity.

<h2>6) Gigawatts (GW) </h2>

We already know the dependent variable in this <u>Wind Energy Capacity vs Years</u> graph is Wind Energy Capacity, and its Unit is Gigawatts (GW).

Where $1GW=10^{6} W$

<h2>7) Both onshore and offshore wind sources </h2>

When we talk about scientific experimentation and representing data, the Control Variable is the one that remains constant (it does not change during the investigation).

According to the explanation above, the option that fits with this characteristic is: Both onshore and offshore wind sources

If we want to make a linear interpolation to estimate how much wind energy capacity was there in the United States in the middle of 2011, firstly we need to <u>find two points where the value we want to find is in the middle.</u>

These points (X,Y) are:

P1: (2011,48) and P2: (2012,60)

Where X1:2011, Y1:48, X2:2012, Y2:60

Now we find the <u>slope</u> $m$ of the line with the following equation:

$m=\frac{Y2 - Y1}{X2 - X1}$

$m=\frac{60 - 48}{2012 - 2011}=12$

Then, with this value of the slope we can write the <u>equation of the line</u> and find the <u>intersection point</u> $b$ with one of the given points (we will use P1):

$Y=mX+b$

$48=12(2011)+b$

$b=-24084$

With this value and the slope, we can find Y for X=2011.5 (we need to know the wind capacity in the middle of 2011):

$Y=(12)(2011.5)-24084$

$Y=54$ This is the e<u>stimated result</u> 54 GW, and the option that is near this value is 55 GW

In this case we will apply a similar method as the previous answer, but estimating a prediction:

Let's find two points near the value we want to find. These points (X,Y) are:

P1: (2014,22) and P2: (2016,29)

Where X1:2014, Y1:22, X2:2016, Y2:29

Now we find the <u>slope</u> $m$ of the line with the following equation:

$m=\frac{Y2 - Y1}{X2 - X1}$

$m=\frac{29 - 22}{2016 - 2014}=\frac{7}{2}$

Then, with this value of the slope we can write the <u>equation of the line</u> and find the <u>intersection point</u> $b$ with one of the given points (we will use P2):

$Y=mX+b$

$29=\frac{7}{2}(2016)+b$

$b=-7027$

With this value and the slope, we can find Y for X=2020 (we need to estimate the expected wind capacity in 2020):

$Y=\frac{7}{2}(2020)-7027$

$Y=43$ This is the e<u>stimated result</u> 43 GW (note linear extrapolation is not as accurate as other methods), and the option that is near this value is 36 GW