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Lynna [10]
2 years ago
11

3. A 0.145 kg ball moving horizontally at 20 m/s is struck by a bat that causes the ball to move in the

Physics
1 answer:
kumpel [21]2 years ago
7 0

Answer:

F = 1015 N

Explanation:

Given that,

Mass of a ball, m = 0.145 kg

Initial speed, u = 20 m/s

Final speed, v = -15 m/s (as it moves in opposite direction)

The ball and bat were in contact for 5 ms

We need to find the force the bat applies to the bat. We know that,

F = ma

F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.145\times (-15-20)}{5\times 10^{-3}}\\\\F=-1015\ N

So, the bat will apply 1015 N force to the ball.

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Why is the overall charge of the atom neutral or zero?
MrRissso [65]

Answer:

B

Explanation:

this is because the neutrons do not have a charge, the things that have charge in an atom are electrons and protons.

and in the nucleus of an atom, there are protons and neutrons so you can see that A is not the answer

if you see the periodic table, you will know that the number of electrons and protons are equal, so the charges cancel each other out, hence the charge of an atom will be neutral

let me give you a tip which I got from my teacher, never write there is no charge in the atom, this suggests that there is no protons or electrons.

instead, write, the it is neutral

hope it helps if not please report it so that someone else gets to try it out

7 0
3 years ago
What is the distance traveled when a car goes 20 m/s for 60 seconds?
AfilCa [17]

Answer:

1200 m

Explanation:

s= vt

s= 20m/s × 60 s

s= 1200 m

hope it hepls

for any question comment me ❤❤

5 0
3 years ago
Describe what it means if a chemical or physical property is periodic
vesna_86 [32]
It means that you consider the elements as a list organized by atomic number, the property is seen to repeat over and over as you move through that list.
6 0
3 years ago
You push a coin across a table. The coin stops. How does this motion relate to balanced and unbalanced forces?
Snezhnost [94]
If you are pushing the coin across the table at a constant rate, the friction of the table and the horizontal force of your hand pushing are equal, and the coin itself moves at a constant rate. If you push a coin and let it go, there is no horizontal force keeping the coin going. Friction slows the coin to a stop. In both cases, the gravitational downward pull of Earth is equally but oppositely resisted by the upward push of table on the coin.
7 0
2 years ago
The magnitude of each force is 208 N the force on the right is applied at an angle 36° and the mass of the block is 17 kg the co
djyliett [7]

Answer:

<em>11.06m/s²</em>

Explanation:

According to Newtons second law of motion

\sm F_x = ma_x\\F_m - F_f = ma_x\\mgsin \theta - \mu R mgcos \theta = ma_x\\

Given

Mass m = 17kg

Fm = 208N

theta = 36 degrees

g = 9.8m/s²

a is the acceleration

Substitute

208 - 0.148(17)(9.8)cos 36 = 17a

208 - 24.6568cos36 = 17a

208 - 19.9478 = 17a

188.05 = 17a

a = 188.05/17

a = 11.06m/s²

<em>Hence the  the magnitude of the resulting acceleration is 11.06m/s²</em>

6 0
2 years ago
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