<span>A person expended 500 newtons to move a full wheelbarrow 30 meters how much work was done?
</span>In physics, a force is said to do work<span> if, when acting, there is a displacement of the point of application in the direction of the force. The work done would be calculated as follows:
</span>
W = F x d = 500 N (30 m) = 15000 J or 15 kJ
Answer:
a. Initial speed is zero from a crouching position...
b... Mass of body * 9.8
Explanation:
Answer:
I'm fairly sure that the answer is "100 m/s"
Explanation:
Fnet=ma
a=Fnet/m
a=4 N / 0.040 kg
a=100 m/s
please check my work before you submit, i don't wanna let cha down :)
gravity? I am not completly sure but this is my best guess
F = M (V^2/r) = 20 x 100 /.15 =13333.33 N<span>convert units as needed to wind up with Newtons Kg-m/s^2 hope it helps :)</span>