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Lynna [10]
3 years ago
11

3. A 0.145 kg ball moving horizontally at 20 m/s is struck by a bat that causes the ball to move in the

Physics
1 answer:
kumpel [21]3 years ago
7 0

Answer:

F = 1015 N

Explanation:

Given that,

Mass of a ball, m = 0.145 kg

Initial speed, u = 20 m/s

Final speed, v = -15 m/s (as it moves in opposite direction)

The ball and bat were in contact for 5 ms

We need to find the force the bat applies to the bat. We know that,

F = ma

F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.145\times (-15-20)}{5\times 10^{-3}}\\\\F=-1015\ N

So, the bat will apply 1015 N force to the ball.

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A gas‑forming reaction produces 1.90 m 3 1.90 m3 of gas against a constant pressure of 179.0 kPa. 179.0 kPa. Calculate the work
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Answer:

The work done is 3.4 × 10⁵ J.

Explanation:

Given:

Pressure of the gas produced (P) = 179 kPa

Volume of the gas produced (ΔV) = 1.90 m³

We need to find the work done in joules. For that, we don't need any conversion as the units are already in SI units which will give the result in Joules only.

Now, let us verify our results by using conversion factors and without using them.

Using conversion factors:

1 m³ = 1000 L

So, 1.90 m³ = 1.90 m³ × 1000 \frac{L}{m^3} = 1900 L

Also, 1 atm = 101.325 kPa

So, 179 kPa = 179 kPa × \frac{1\ atm}{101.325\ kPa} = 1.767 atm

Now, work done in a constant pressure process is given as:

Work = Pressure × Volume change

Work = P × ΔV

Work = 1.767 atm × 1900 L

Work = 3.36 × 10³ atm-L

Now, again using the energy conversion for work.

1 atm-L = 101.325 J

So, 3.36 × 10³ atm-L = 3.36 × 10³ atm-L × \frac{101.325\ J}{1\ atm-L} = 3.4 × 10⁵ J

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Now, let us verify the above result without any conversion.

Work = P × ΔV = 179 × 1000 × 1.90 = 3.4 × 10⁵ J.

Therefore, the work done is same by both ways.

Hence the work done is 3.4 × 10⁵ J.

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Answer:

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Explanation:

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