Answer:
V₂ = 14.07 L
Explanation:
As this gas is cooled at constant temperature of 320 K, this means that we are on an isothermal process, and according to the 1st law of thermodynamics:
Q = W (1)
And as the temperature is constant, we can use the following expression to calculate the Work done:
W = nRT ln(V₁/V₂) (2)
However, as Q = W, we can replace heat into the above expression and then solve for V₂:
Q = nRT ln(V₁/V₂)
Replacing we have:
1200 = (1.5 * 8.314 * 320) ln(19/V₂)
1200 = 39907.2 ln(19/V₂)
ln(19/V₂) = 1200/3990.72
ln(19/V₂) = 0.3007
19/V₂ = e^(0.3007)
V₂ = 19 / e^(0.3007)
<h2>
V₂ = 14.07 L</h2>
Hope this helps
Answer:
It would be lower than because, if the boiling point of that element is 77 Kelvin degrees then if it isn’t at boiling point it would automatically be cooler than that. Even if it’s at its original state. The normal temperature of Liquid Nitrogen is really cold -320.8 degrees.
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Answer:
The answer is
<h2>28 kg</h2>
Explanation:
The mass of an object given it's momentum and velocity / speed can be found by using the formula
where
m is the mass
p is the momentum
v is the speed or velocity
From the question
p = 280 kg/ms
v = 10 m/s
The mass of the object is
We have the final answer as
<h3>28 kg</h3>
Hope this helps you
