All categories

2 years ago

Brenda is cooking couscous. The recipe says she requires 480 grams of couscous for 4 people. How many will she need for 14?

Mathematics

1 answer:

Nimfa-mama [501]2 years ago

8 0

Answer:

1,680 grams

Step-by-step explanation:

To solve this, we can create a proportion using this setup:

grams/people=grams/people

The recipe needs 480 grams for 4 people and x (unknown-what we are trying to find) grams for 14 people.

480 grams/4 people=x grams/14

480/4=x/14

Now, we have to solve for x-the grams needed for 14 people. To do this, we have to get x by itself. x is being divided by 14. To undo this, multiply both sides by 14, because multiplication is the opposite of division.

14(480/4)=(x/14)14

14(480/4)=x

14*120=x

1680=x

She needs 1,680 grams of couscous for 14 people.

You might be interested in

How can you use exponential growth or exponential decay to model the populations of endangered species?

hammer [34]

Answer:

help animals and clean up to help animals animals are friends not food

6 0

3 years ago

Read 2 more answers

18. Two planes left an airport at the same time. One flew north at a set speed and the other

Andre45 [30]

Answer: plane A = 333.33mph

Plane B = 500mph

Step-by-step explanation:

Given data:

Distance between the two planes = 2400miles.

Plane A flew North

Plane B flew south

Solution:

Let v represent plane A.

Let 2v represent plane B.

Distance between the two plane

v + 1.5* v = 3*v

7.5v = 2500miles

v = 333.33mph

Plane B has one and half times the speed of plane A

= 1.5 * 333.33

= 500mph

4 0

2 years ago

.Which one of the following is true when ds/dt=3t^2/2s

ser-zykov [4K]

1) Given: ds / dt = 3t^2 / 2s

2) Separate variables: 2s ds = 3t^2 dt

3) Integrate both sides:

∫ 2s ds = ∫ 3t^2 dt

s^2 + constant = t^3 + constant

=> s^2 = t^3 + constant

=> s = √ (t^3 + constant)

Answer: option B.

4 0

3 years ago

NEED HELP ASAP!!! THX Determine if the two figures are congruent and explain your answer. Attachment

Norma-Jean [14]

I need the attachment that goes with it

8 0

3 years ago

Read 2 more answers

On a given day, machine A has a 10% chance of malfunctioning and machine B has a 7% chance of the same. Given that at least one

valentinak56 [21]

I will give an instance to answer this. Suppose that we have 1,000 days. And it was given above that machine A has 10 % chances to malfunctioned and B has a 7%. So machine A has 100 days that malfunctioned while machine B has 70 days. And 7 days that both machines malfunctioned (10%x7%). Next is to add 100 days from machine A and 70 days from machine B and subtract with the 7 days where both of them malfunctioned. So the result is 163 days out of 1000 that we expect an incidence of failure. So the chance of machine B to malfunctioned is 70 days. 70/163 is 42.93%

4 0

2 years ago