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morpeh [17]
3 years ago
12

3 + root 3 *2 +root 2​

Mathematics
1 answer:
icang [17]3 years ago
4 0

Answer:

6 + 3\sqrt{2} + 2\sqrt{3} + \sqrt{6}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Given

(3 + \sqrt{3} )(2 + \sqrt{2} )

Each term in the second factor is multiplied by each term in the first factor, that is

3(2 + \sqrt{2} ) + \sqrt{3} (2 + \sqrt{2} ) ← distribute both parenthesis

= 6 + 3\sqrt{2} + 2\sqrt{3} + \sqrt{6}

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