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3 years ago

3 + root 3 *2 +root 2

Mathematics

1 answer:

icang [17]3 years ago

4 0

Answer:

6 + 3 $\sqrt{2}$ + 2 $\sqrt{3}$ + $\sqrt{6}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Given

(3 + $\sqrt{3}$ )(2 + $\sqrt{2}$ )

Each term in the second factor is multiplied by each term in the first factor, that is

3(2 + $\sqrt{2}$ ) + $\sqrt{3}$ (2 + $\sqrt{2}$ ) ← distribute both parenthesis

= 6 + 3 $\sqrt{2}$ + 2 $\sqrt{3}$ + $\sqrt{6}$

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Step-by-step explanation:

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3 years ago

Parcc chapter 7 pythagorean theorem

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3 years ago

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