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2 years ago

9

Fifteen more than twice a number is 9

1 answer:

Elden [556K]2 years ago

7 0

2x+15=9
2x= -6
so the answer is -3

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The graph shows the ratio of goals attempted to goals made for two soccer players, Andres and Deyvi. Which player has a better r

anygoal [31]

Answer: Andres

Explanation:

y = goals made

x = goals attempted

For Andres, his ratio is y/x = 4/8 = 1/2 = 0.50 meaning that he made 50% of his attempts

For Deyvi, the ratio is y/x = 9/20 = 0.45 = 45%

Andres has the better record.

4 0

1 year ago

What is 5+2????????????????/

Amiraneli [1.4K]

Answer:well after careful consideration it’s 7

Step-by-step explanation: 1+1+1+1+1+1+1=7

4 0

2 years ago

If P is the orthocenter of △ABC, AB = 13, BF = 9,and FC = 5.6, find each measure & the perimeter of triangle ABC.

harina [27]

Answer:

$Perimeter = 38.6$

Step-by-step explanation:

Given

$A\ B = 13$

$B\ F = 9$

$F\ C = 5.6$

Required

Calculate the perimeter of A B C

To calculate the perimeter of A B C, we sum up the sides of the triangle

i.e.

$Perimeter = A B + B\ C + A\ C$

AB is given in the question already.

So, we need to calculate B F and F C

To solve for BF, we consider triangle B F C

Using Pythagoras Theorem, we have:

$B\ C^2 = B\ F^2 + F\ C^2$

Substitute values for BF and FC;

$B\ C^2 = 9^2 + 5.6^2$

$B\ C^2 = 81 + 31.36$

$B\ C^2 = 112.36$

$B\ C^2= \sqrt{112.36$

$B\ C = 10.6$

Next, we calculate A C.

To calculate A C, we need to calculate A F, considering triangle B F A

Using Pythagoras Theorem, we have:

$A\ B^2 = B\ F^2 + A\ F^2$

Substitute values for B F and A B;

$13^2 = 9^2 + A\ F^2$

$169= 81 + A\ F^2$

$A\ F^2 = 169 - 81$

$A\ F^2 = 88$

$A\ F = \sqrt{88$

$A\ F = 9.4$

Since F lies on line A C:

$A\ C = A\ F + F\ C$

$A\ C = 9.4 + 5.6$

$A\ C = 15.0$

Recall that:

$Perimeter = A\ B + B\ C + A\ C$

$Perimeter = 13 + 10.6 + 15.0$

$Perimeter = 38.6$

<em>Hence, the perimeter is 38.6</em>

3 0

2 years ago

Which of the following equations represents a horizontal line through (5,-3)?

Snowcat [4.5K]

X=5 vertical all the best

3 0

2 years ago

Read 2 more answers

Studentka2010 [4]

Answer:

The area of the shaded portion of the figure is $9.1\ cm^2$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The shaded area is equal to the area of the square less the area not shaded.

There are 4 "not shaded" regions.

step 1

Find the area of square ABCD

The area of square is equal to

$A=b^2$

where

b is the length side of the square

we have

$b=4\ cm$

substitute

$A=4^2=16\ cm^2$

step 2

We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):

The area of circle is equal to

$A=\pi r^{2}$

The diameter of the circle is equal to the length side of the square

so

$r=\frac{b}{2}=\frac{4}{2}=2\ cm$ ---> radius is half the diameter

substitute

$A=\pi (2)^{2}$

$A=4\pi\ cm^2$

Therefore, the area of 2 "not-shaded" regions is:

$A=(16-4\pi) \ cm^2$

and the area of 4 "not-shaded" regions is:

$A=2(16-4\pi)=(32-8\pi)\ cm^2$

step 3

Find the area of the shaded region

Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:

so

$A=16-(32-8\pi)=(8\pi-16)\ cm^2$

---> exact value

assume

$\pi =3.14$

substitute

$A=(8(3.14)-16)=9.1\ cm^2$

8 0

2 years ago