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Elis [28]
4 years ago
14

Whats 48.5438 x 16 1/7 divided by 8?

Mathematics
1 answer:
Vlad1618 [11]4 years ago
6 0

Answer:

97.95

Step-by-step explanation:

48.5438 x 16 1/7 = 783.6356286

783.6356286 ÷ 8 =97.95445357

round- 97.95

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Help pls A sign in a bakery gives these options: 12 cupcakes for $29, 24 cupcakes for $56, and 50 cupcakes for $129 a) Find each
allsm [11]

Answer:

A) $2.42, $2.33, $2.58

B) The cheapest deal is 24 for $56

Step-by-step explanation:

6 0
3 years ago
Find the simple interest on a loan of:
Nikolay [14]

Answer:

simple interest= 5100

using formula SI=<u> </u><u>PTR</u>

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hope it helps..

7 0
3 years ago
20 copies of the school yearbook together weigh 50 lb what is the weight of each book
dedylja [7]

Answer:

2.5 pounds per book

Step-by-step explanation:

Set up a proportion

20 copies / 50 pounds = 1 copy / x pounds

Cross multiply

20x = 50

Divide both sides by 20

x = 2.5 pounds


I hope this helped and please mark me as brainliest!

6 0
2 years ago
Red 25 green 10 blue 15 probability of the green
Leto [7]
Total = 25 + 10 + 15 = 50
Green = 25

P(green) = 25/50  = 1/2

Answer: 1/2
7 0
4 years ago
Read 2 more answers
5. A company sells small, colored binder clips in packages of 20 and offers a money-back guarantee if two or more of the clips a
SOVA2 [1]

Answer:

a) Binomial.

b) n=20, p=0.01, k≥2

The probability hat a package sold will be refunded is P=0.0169.

Step-by-step explanation:

a) We know that

  • the defective probability is constant and independent.
  • the sample size is bigger than one subject.

The most appropiate distribution to represent this random variable is the binomial.

b) The parameters are:

  • Sample size (amount of clips in the package): n=20
  • Probability of defective clips: p=0.01.
  • number of defective clips that trigger the money-back guarantee: k≥2

The probability of the package being refunded can be calculated as:

P(x\geq2)=1-(P(x=0)+P(x=1))\\\\\\P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}\\\\\\P(x=0) = \dbinom{20}{0} p^{0}q^{20}=1*1*0.8179=0.8179\\\\\\P(x=1) = \dbinom{20}{1} p^{1}q^{19}=20*0.01*0.8262=0.1652\\\\\\P(x\geq2)=1-(0.8179+0.1652)=1-0.9831=0.0169

6 0
4 years ago
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