All categories

3 years ago

Both Daniel and Chris are 4 feet 6 inches tall. What is their combined height?

Mathematics

2 answers:

kkurt [141]3 years ago

8 0

You take 4 (Daniel height) and add it to 6 (Chris height) =10 inches

mafiozo [28]3 years ago

7 0

All you have to do is add 4+6 and that equals 10, so your answer is therefor 10

I hope this helps. ;)

You might be interested in

Find the area of a polygon with the given vertices A(2,2) B(5,2) C(3,-1) D(0,-1)<br><br> Number 21

Bogdan [553]

Answer:

Je pense que je ne sais pas vraiment

6 0

2 years ago

Which numerical expression represents the value (in cents) of 12 dimes?

bekas [8.4K]

B is the answer since dimes are worth 10 cents

4 0

3 years ago

Read 2 more answers

he pulse rates of 179 randomly selected adult males vary from a low of 43 bpm to a high of 115 bpm. Find the minimum sample size

malfutka [58]

Answer:

Step-by-step explanation:

Given that:

Low = 43bpm

High = 115 bpm

Error = 3

α = 90%

To find the range estimate :

Standard destviation = (high - low) / 4

Standard deviation = (115 - 43) / 4

Standard deviation = 72/4 = 18

The sample size,(n) :

n = [(Zα/2 * sd)/E] ²

2 - tail = (Zα/2) = 1.645

[(Zα/2 * sd)/E] ² = [(1.645 * 18) / 3]² = (29.61/3)²

= 97.41

Sample size = 97

5 0

3 years ago

Bill Gates wrote a computer program that generates three random numbers

Allushta [10]

Answer:

1/1000

Step-by-step explanation:

The probability of two independent events A, B (independent = events that do not depend on each other) is given by the product of the individual probabilities of A and B:

$p(AB)=p(A)\cdot p(B)$ (1)

In this problem, the single event is "getting a 3" when extracting a random number between 1 and 10.

The total number of possible outcomes is

n = 10

While the number of succesfull outcomes (getting a 3) is only one:

$s=1$

So, the probability of drawing a 3 in 1 draw is

$p(3)=\frac{s}{n}=\frac{1}{10}$

Then, we want to find the probability of getting three "3" in 3 consecutive generations. These events are independent events, so we can use rule (1) to find the total probability, and we get:

$p(333)=p(3)p(3)p(3)=(\frac{1}{10})(\frac{1}{10})(\frac{1}{10})=\frac{1}{1000}$