Answer:
angle 3. ( x ) is 136°
angle 4 ( y ) is 44° !!
Step-by-step explanation:
Let angle 3 be x and angle 4 be y
Given, Angle 3 and angle 4 form a linear pair
x + y = 180 [ sum of linear pair angle is 180 ] ... ( i )
Also, The measure of Angle 3 is four more than three
The measure of Angle 3 is four more than threetimes the measure of angle 4.
x = 4 + 3y .... ( ii )
Putting value of x from ( ii ) in ( i )
4 + 3y + y = 180
4y = 176
y = 44
Also, x + y = 180 => x = 180 - 44 = 136
Solution:
As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.
We consider a line , one dimensional if it's thickness is negligible.
So, Line is two dimensional if it's thickness is not negligible becomes a quadrilateral.
So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.
(0.1x-22)+(0.3x-54)=90
First combine like terms
0.4x - 76 = 90
Now add 76 on both sides
0.4x = 166
Divide by 0.4 on each side to isolate x
X= 415
1-m
2-y
3-e
should be the answers to the question