Question

23 14

Answer 1

Answer:

(A). The horizontal initial velocity is 25 m/s.

(B).  The vertical initial velocity is 43.3 m/s.

(C). The velocity component is

$u_{x}=u\cos\theta$

$u_{y}=u\sin\theta$

Explanation:

Given that,

Initial velocity = 50.0 m/s

Angle = 60°

We need to calculate the component of velocity

Using formula of component

(A). Horizontal initial velocity

$\cos\theta=\dfrac{u_{x}}{u}$

Put the value in to the formula

$\cos60=\dfrac{u_{x}}{50}$

$u_{x}=50\times\cos60$

$u_{x}=25\ m/s$

(B). Vertical initial velocity

$\sin\theta=\dfrac{u_{y}}{u}$

Put the value in to the formula

$\sin60=\dfrac{u_{y}}{50}$

$u_{y}=50\times\sin60$

$u_{y}=43.3\ m/s$

The velocity component is

$u_{x}=u\cos\theta$

$u_{y}=u\sin\theta$

Hence, (A). The horizontal initial velocity is 25 m/s.

(B).  The vertical initial velocity is 43.3 m/s.

(C). The velocity component is

$u_{x}=u\cos\theta$

$u_{y}=u\sin\theta$