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3 years ago

Calculate the force on an object that has a mass of 12 kg and an acceleration of 4 m/s^2

Physics

1 answer:

kati45 [8]3 years ago

8 0

Remember Newton's Second Law F = mass * acceleration

mass = 12 kg
acceleration = 4 m/s^2

F = 12 * 4 = 48 N

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Explanation:

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3 years ago

A diffraction grating with 600 lines/mmlines/mm is illuminated with light of wavelength 510 nmnm. A very wide viewing screen is

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Answer:

A.2.95 m

B.7

Explanation:

We are given that

Diffraction grating=600 lines/mm

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A.We have to find the distance between the two m=1 bright fringes

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$\theta=sin^{-1}(0.305)=17.76^{\circ}$

The distance between two m=1 fringes

$x=2ltan\theta=2\times 4.6 tan(17.76^{\circ})=2.95 m$

Hence, the distance between two m=1 fringes=2.95 m

B.For maximum number of fringes,

$sin\theta=1$

$sin\theta=\frac{m\lambda}{d}$

Substitute the values

$1=\frac{m\times 510\times 10^{-9}}{1.67\times 10^{-6}}$

$m=\frac{1.67\times 10^{-6}}{510\times 10^{-9}}=3.3\approx 3$

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4 years ago

An object has a coefficient of kinetic friction of 0.2 and a normal force of 30N. Find the force of kinetic friction.

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Answer:

Force of kinetic friction, Fk = 6N

Explanation:

Given the following data;

Coefficient of kinetic friction, μ = 0.2

Normal force, Fn=30N

To find the Force of kinetic friction;

Mathematically, the force of kinetic friction is given by the formula;

Fk = μFn

Where;

Fk represents the force of kinetic friction.

μ represents the coefficient of friction.

Fn represents the normal force.

Substituting into the equation, we have;

Fk = 0.2*30

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Therefore, the force of kinetic friction is 6N.

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3 years ago

How to calculate kinetic energy using potential energy

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It’s literally in your reading go re reas

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3 years ago

Two small plastic spheres each have a mass of 1.1 g and a charge of -50.0 nC . They are placed 2.1 cm apart (center to center).

Solnce55 [7]

Answer:

Part a)

F = 0.051 N

Part b)

Both spheres will follow Newton's III law of action reaction force so both sphere will have same force of equal magnitude.

Explanation:

Part a)

Electrostatic force between two charged spherical balls is given as

$F = \frac{kq_1q_2}{r^2}$

here we will have

$q_1 = q_2 = 50 nC$

here the distance between the center of two balls is given as

$r = 2.1 cm = 0.021 m$

now we will have

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$F = 0.051 N$

Part b)

Both spheres will follow Newton's III law of action reaction force so both sphere will have same force of equal magnitude.

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3 years ago