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Luba_88 [7]
3 years ago
10

ANSWER PLS!! ---------------------

Physics
1 answer:
ELEN [110]3 years ago
8 0

Answer:

dry wood

Explanation:

plzzzzzzz Mark my answer in brainlist

and follow me

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A beam of light strikes a mirror at angle of 23° to the normal. What is the angle between the incident and reflected beam?
My name is Ann [436]

Answer:

well, during reflection

angle of incident is equal to angle of reflection so if angles of incident is 23° , then angle of reflection is also equal to 23° .

so the total angle between the reflected and incident ray will be equal to angle of incidence plus angle of reflection

i.e. angle i + angle r = 23° + 23° = 46°

hence the required angle is 46°

<em>i</em><em> </em><em>hope</em><em> </em><em>it</em><em> </em><em>helped</em><em> </em><em>.</em>

4 0
3 years ago
Aplicar ley de Seno y Coseno
ycow [4]

Answer:

Es 100000

Explanation: qppp-100

7 0
3 years ago
__________, the best forecasting methods to use are time series models such as moving average. ANSWER Unselected When the future
DochEvi [55]

Answer:

Greetings!

The correct answer is the last one, "When the future level of some variable is seen as a function other than time".

Explanation:

Along other forecasting methods, the moving average finds utility in cases when seasonality is a factor. This term refers to a set of variables unknown to (or uncontrolled by) the observer that influence the series model in some way.

By applying a moving average to a time series one can mitigate such irregular effects.

I hope this helps!

8 0
3 years ago
How fast must a train accelerates from rest to cover 518 m in the first 7.48 s?
Rus_ich [418]

Heya!

For this problem, use the formula:

s = Vo * t + (at^2) / 2

Since the initial velocity is zero, the formula simplifies like this:

s = (at^2) / 2

Clear a:

2s = at^2

(2s) / t^2 = a

a = (2s) / t^2

Data:

s = Distance = 518 m

t = Time = 7,48 s

a = Aceleration = ¿?

Replace according formula:

a = (2*518 m) / (7,48 s)^2

Resolving:

a = 1036 m / 55,95 s^2

a = 23,34 m/s^2

The aceleration must be <u>23,34 meters per second squared</u>

8 0
3 years ago
You shoot an arrow into the air. Two seconds later (2.00 s) the arrow has gone straight upward to a height of 35.0 m above its l
sdas [7]

This question can be solved by using the equations of motion.

a) The initial speed of the arrow is was "9.81 m/s".

b) It took the arrow "1.13 s" to reach a height of 17.5 m.

a)

We will use the second equation of motion to find out the initial speed of the arrow.

h= v_it + \frac{1}{2}gt^2\\

where,

vi = initial speed = ?

h = height = 35 m

t = time interval = 2 s

g = acceleration due to gravity = 9.81 m/s²

Therefore,

35\ m = (v_i)(2\ s)+\frac{1}{2}(9.81\ m/s^2)(2\ s)^2\\\\v_i(2\ s)=19.62\ m\\\\v_i = \frac{19.62\ m}{2\ s}

<u>vi =  9.81 m/s</u>

b)

To find the time taken by the arrow to reach 17.5 m, we will use the second equation of motion again.

h= v_it + \frac{1}{2}gt^2\\

where,

g = acceleration due to gravity = 9.81 m/s²

h = height = 17.5 m

vi = initial speed = 9.81 m/s

t = time = ?

Therefore,

17.5 = (9.81)t+\frac{1}{2}(9.81)t^2\\4.905t^2+9.81t-17.5=0

solving this quadratic equation using the quadratic formula, we get:

t = -3.13 s (OR) t = 1.13 s

Since time can not have a negative value.

Therefore,

<u>t = 1.13 s</u>

Learn more about equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

4 0
2 years ago
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