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Zanzabum
3 years ago
12

Does laser refract through water or reflect ?

Physics
2 answers:
Novosadov [1.4K]3 years ago
7 0

Answer:

Calm water looks like a mirror from below because underwater light is entirely reflected when it comes from beyond a certain angle. This so-called total internal reflection also allows low power lasers to bend the waters surface.

thank you

pls mark as BRAINLIST

NemiM [27]3 years ago
3 0

Answer:

If you shine a light straight down at water, most of the light will go into the water, and some will reflect.

SO that would means:

- Laser would refract throught the water (in some part of it)

- But laser would also reflect from the water surface (in another part of it )

Another easy example:

- Sunshine go through water? (yes in the first few meters)

- Sunshine reflect with water? (yes, most of them would reflect )

Hope this helped :3

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3 years ago
A 5 m3 tank containing 5kg of an unknown ideal gas at 500 kPa is connected through a valve to another tank containing 10 kg of t
Ivan

Answer:

a) V_{T} = 9\,m^{2}, b) m_{T} = 15\,kg, c) P_{T} = 416.667\,kPa

Explanation:

a) The equation of state for ideal gas is:

P \cdot V = \frac{m}{M}\cdot R_{u}\cdot T

Given the existence of an isothermal process, the following relation is derived:

\frac{P_{1}\cdot V_{1}}{m_{1}} = \frac{P_{2}\cdot V_{2}}{m_{2}}

The volume of the other tank is:

V_{2} = \left(\frac{m_{2}}{m_{1}} \right)\cdot \left(\frac{P_{1}}{P_{2}}\right)\cdot V_{1}

V_{2} = \left(\frac{10\,kg}{5\,kg} \right)\cdot \left(\frac{200\,kPa}{500\,kPa}\right)\cdot (5\,m^{3})

V_{2} = 4\,m^{3}

The total volume is:

V_{T} = V_{1} + V_{2}

V_{T} = 5\,m^{3} + 4\,m^{3}

V_{T} = 9\,m^{2}

b) The total mass is:

m_{T} = m_{1} + m_{2}

m_{T} = 5\,kg + 10\,kg

m_{T} = 15\,kg

c) The pressure of the gas in the two tanks is:

P_{2} = \left(\frac{m_{2}}{m_{1}} \right)\cdot \left(\frac{V_{1}}{V_{2}}\right)\cdot P_{1}

P_{T} = \left(\frac{15\,kg}{5\,kg}\right)\cdot \left(\frac{5\,m^{2}}{9\,m^{2}} \right)\cdot (500\,kPa)

P_{T} = 416.667\,kPa

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4 years ago
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Answer:

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Explanation:

6 0
3 years ago
1 mole of air undergoes a Carnot cycle. The hot reservoir is at 800 oC and the cold reservoir is at 25 oC. The pressure ranges b
BabaBlast [244]

Answer:

The net work produced is 30.37 KJ

The efficiency of cycle is 72.3%

Explanation:

For the net work produced, we have the formula:

Work = (Th - Tc)(Sh - Sc)(M)

Where,

Th = higher temperature = 800° C + 273 = 1073 k

Tc = lower temperature = 25° C + 273 = 298 k

Sh = specific entropy at higher temperature

Sc = specific entropy at lower temperature

M = molar mass of air

Using, ideal gas table to find entropy. The table is attached.

therefore,

Work = (1073 k - 298 k)(3.0485235 KJ/kg.k - 1.69528 KJ/kg.k)(0.02896 kg)

Work = (775 k)(1.3532435 KJ/kg.k)(0.02896 kg)

<u>Work = 30.37 KJ</u>

Now, for the efficiency (n), we have a formula:

n = 1 - Tc/Th

n = 1 - (298 k)/(1073 k)

<u>n = 0.723 = 72.3 %</u>

5 0
4 years ago
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