Answer:
(r o g)(2) = 4
(q o r)(2) = 14
Step-by-step explanation:
Given


Solving (a): (r o q)(2)
In function:
(r o g)(x) = r(g(x))
So, first we calculate g(2)




Next, we calculate r(g(2))
Substitute 9 for g(2)in r(g(2))
r(q(2)) = r(9)
This gives:


{

Hence:
(r o g)(2) = 4
Solving (b): (q o r)(2)
So, first we calculate r(2)




Next, we calculate g(r(2))
Substitute 3 for r(2)in g(r(2))
g(r(2)) = g(3)




Hence:
(q o r)(2) = 14
U must find the median, the range, and the mode. And that is your answer
Answer:
C) There is not sufficient evidence to support the claim that the mean attendance is greater than 523.
Step-by-step explanation:
Let μ be the the average attendance at games of the football team
The claim: the average attendance at games is over 523
Null and alternative hypotheses are:
: μ=523
: μ>523
The conclusion is failure to reject the null hypothesis.
This means that <em>test statistic</em> is lower than <em>critical value</em>. Therefore it is not significant, there is no significant evidence to accept the <em>alternative</em> hypothesis.
That is no significant evidence that the average attendance at games of the football team is greater than 523.
In order to do mean you have to add all of the numbers in the list together. then divide them by the total amount of numbers (ex. 7,9,3,2,5. you would add all of these up 7+9+3+2+5=26 then you would divide that by 5 because there are five numbers in the list.
It is 1/3, add up the total number of kids, which is 30, the number of kids 6-8 is 10. 10/30 is equivalent to 1/3