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3 years ago

Find the value of x.need the answer today please.Thank you.

Mathematics

2 answers:

jeka943 years ago

7 0

Answer:

↓ Look below ↓

Step-by-step explanation:

You are given the adjacent side and need to find the hypotenuse. You can use cos to figure this out.

$cos33 = \frac{7}{x}$

→To get rid of the x in the denominator, multiply everything by x:

$x(cos33 = \frac{7}{x})$

$xcos33 = 7$

→Divide both sides by cos33:

x = 8.346

→If it is round to nearest tenth:

x = 8.3

→If it is round to nearest hundredth:

x = 8.35

charle [14.2K]3 years ago

3 0

Answer:

x =8.34654305

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adjacent / hypotenuse

cos 33 = 7/x

Switching places with the x and the 33

x = 7/ cos 33

x =8.34654305

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3 years ago

What are the solutions to the following system?

bija089 [108]

The solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Solution:

Given equation:

$-2 x^{2}+y=-5$

Add $2 x^{2}$ on both sides.

$-2 x^{2}+y+2 x^{2}=-5+2 x^{2}$

$y=-5+2 x^{2}$ -------- (1)

$y=-3 x^{2}+5$ (given) -------- (2)

Equate (1) and (2).

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Add $3 x^{2}$ on both sides.

$-5+2 x^{2}+3 x^{2}=-3 x^{2}+5 +3 x^{2}$

$-5+5x^{2}=5$

Add 5 on both sides.

$-5+5x^{2}+5=5+5$

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Divide by 5 on both sides, we get

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Taking square root on both sides, we get

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Substitute $x=-\sqrt{2}$ in (1).

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$y=-5+4$

$y=-1$

Therefore the solutions are $(\sqrt{2},-1) \text { and }(-\sqrt{2},-1)$ .

Option C is the correct answer.

6 0

3 years ago

Help me PLEASE!!!!! 3x = 27 x = ? Thank you!!

steposvetlana [31]

We will use the INVERSE OPERATION of multiplication which is division. Lets do it:-

3x = 27
27 ÷ 3 = x
27 ÷ 3 = 9
x = 9

CHECK OUR WORK:-

3x = 27
x = 9
3 · 9 = 27
We were RIGHT!!!!!

So, x = 27.

Hope I helped ya!!! xD

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3 years ago

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Find the value of x.need the answer today please.Thank you.​

Find the value of x.need the answer today please.Thank you.