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lawyer [7]
4 years ago
6

Light is described as having a dual wave-particle nature. Which piece of evidence provides support for the model of light as a p

article?
Young’s double slit experiment showed that light waves show interference.

Light reflects when it hits a surface.

Light refracts when it moves from one medium to another.

Light does not need a medium to travel.
Physics
1 answer:
garik1379 [7]4 years ago
8 0
<h2>Answer: Light reflects when it hits a surface.</h2>

Explanation:

It is now clear that light behaves as a wave and as a particle. It should be noted that the first to propose the <u>corpuscular theory </u>of light was <u>Issac Newton</u>, while the <u>wave theory</u> was initially proposed by <u>Christian Huygens</u>, who was contemporaneous with Newton.

Now, focusing on the corpuscular theory, <u>Newton proposed that light is composed of tiny massless particles, traveling in a straight line and at high speed.</u> In addition, he used the reflection phenomenon of the of light to show that it behaved like particles that when hitting a mirror were reflected by a perfectly elastic collision.

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A very fine thread is placed between two glass plates on one side and the other side is touching to form a wedge. A beam of mono
ki77a [65]

Answer:

53.3micro meters

Explanation:

See attached file

4 0
4 years ago
What is the magnitude of the momentum of a 11kg object moving at 2.2 m/s?
tangare [24]

Answer:

<h3>The answer is 24.2 kgm/s</h3>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

mass = 11 kg

velocity = 2.2 m/s

We have

momentum = 11 × 2.2

We have the final answer as

<h3>24.2 kgm/s</h3>

Hope this helps you

4 0
3 years ago
A 10 m long glider with a mass of 680 kg (including the passengers) is gliding horizontally through the air at 30 m/s when a 68
timama [110]

Answer:

 v = 30.39 m/s

Explanation:

given,

mass of glider,M = 680 Kg

mass of the skydiver, m = 68 Kg

horizontal velocity,V = 30 m/s

when skydiver releases, velocity,v = 30 m/s

velocity if the glider,v' =  ?

use the conservation of momentum

M V = m' v' +  m v

m' = 680-68 = 612 Kg

680 x 30 = 612 x v + 60 x 30

612 v = 18600

 v = 30.39 m/s

since the skydiver's speed will be the same as before release

The glider should continue to travel at 30.39 m/s since there are no external forces acting on it

5 0
3 years ago
Water flows with constant speed through a garden hose that goes up to 27.5 cm high. if the water pressure is 132kpa at the botto
sergejj [24]

Answer:

The pressure at the top of the step is 129.303 kilopascals.

Explanation:

From Hydrostatics we find that the pressure difference between extremes of the water column is defined by the following formula, which is a particular case of the Bernoulli's Principle (v_{bottom}\approx v_{top}):

p_{bottom}-p_{top} = \rho\cdot g\cdot \Delta h (1)

p_{bottom}, p_{top} - Total pressures at the bottom and at the top, measured in pascals.

\rho - Density of the water, measured in kilograms per cubic meter.

\Delta h - Height difference of the step, measured in meters.

If we know that p_{bottom} = 132000\,Pa, \rho = 1000\,\frac{kg}{m^{3}}, g = 9.807\,\frac{m}{s^{2}} and \Delta h = 0.275\,m, then the pressure at the top of the step is:

p_{top} = p_{bottom}-\rho\cdot g\cdot \Delta h

p_{top} = 132000\,Pa-\left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.275\,m)

p_{top} = 129303.075\,Pa

p_{top} = 129.303\,kPa

The pressure at the top of the step is 129.303 kilopascals.

6 0
3 years ago
Scientific endeavor is sometimes accompanied by negative tradeoffs.<br> true or false???????????? :0
Ilia_Sergeevich [38]


i think true 
false is false

5 0
3 years ago
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