Question

A soldier on a firing range fires an 8-shot burst from an assault weapon at a full automatic rate of 1000 rounds per minute. Each bullet has a mass of 7.48 g and a speed of 294 m/s relative to the ground as it leaves the barrel of the weapon.Calculate the average recoil force exerted on the weapon during that burst.

Answer 1

Answer:

The average recoil force exerted on the weapon during that burst is 36.65 N

Explanation:

Bullet Mass - m = 7.48 * $10^{-3}$ kg.

Bullet Speed - v = 294 m/s.

This way knowing that for each firing, the time elapsed is

Δt = 60 s / 1000 rounds = 0.06 s / round.

The average recoil force exerted on the weapon during that burst is given by F = -mv/Δt

F = -mv/Δt = -(7.48 * $10^{-3}$ kg)*(294 m/s) / 0.06s = -36.65 N.

The negative sign means it is directed in an opposite direction of the bullet.