The speed of car is 100.8km/h
![KE = \frac{1}{2} m(v \: truck ) {}^{2}](https://tex.z-dn.net/?f=KE%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20m%28v%20%5C%3A%20truck%20%29%20%7B%7D%5E%7B2%7D%20)
![= 0.5 \times 18777 \times \frac{26}{3.6} \times \frac{26}{3.6}](https://tex.z-dn.net/?f=%20%3D%200.5%20%5Ctimes%2018777%20%5Ctimes%20%20%5Cfrac%7B26%7D%7B3.6%7D%20%5Ctimes%20%20%5Cfrac%7B26%7D%7B3.6%7D%20%20)
![= 489708.79j](https://tex.z-dn.net/?f=%20%3D%20489708.79j)
![= \frac{1}{2} \times 1248 \times( v \: car) {}^{2}](https://tex.z-dn.net/?f=%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%201248%20%5Ctimes%28%20v%20%5C%3A%20car%29%20%7B%7D%5E%7B2%7D%20)
![= 624v {}^{2}](https://tex.z-dn.net/?f=%20%3D%20624v%20%7B%7D%5E%7B2%7D%20)
![so \: v {}^{2} = \frac{489708.7}{624}](https://tex.z-dn.net/?f=so%20%5C%3A%20v%20%7B%7D%5E%7B2%7D%20%20%3D%20%20%5Cfrac%7B489708.7%7D%7B624%7D%20)
![= 784](https://tex.z-dn.net/?f=%20%3D%20784)
![v = \sqrt{784}](https://tex.z-dn.net/?f=v%20%3D%20%20%5Csqrt%7B784%7D%20)
![v = 28m/s](https://tex.z-dn.net/?f=v%20%3D%2028m%2Fs)
v car= 28×3.6
=100.8km/h
Hence, the speed of the car is 100.8km/h
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Answer:
The RMS voltage across the resistor = 28 V
Explanation:
Capacitor: A capacitor is an electrical device that has the ability to store electrical charges in an electrical circuit. It is expressed in Farad (F)
Resistor: A resistor is an electrical device that oppose the flow of electric current in a circuit. It is expressed in ohms (Ω)
RMS Voltage : RMS voltage value of an alternating voltage is defined as that value of steady voltage which would dissipate heat at the same rate in a given resistance
Since the it is a series circuit, the total voltage is divided across the resistance and the capacitor.
Vt = V₁ + V₂...........................Equation 1
Where Vt = total Rms voltage = 120 V , V₁ = Rms voltage across the Capacitor = 92 V, V₂ = Rms voltage across the resistor.
Making V₂ the subject of the equation in equation 1 above,
V₂ = Vt - V₁ = 120 - 92
V₂ = 28 V.
The RMS voltage across the resistor = 28 V
4 km in 30 min then 8 km in 60min or an hr. so 8km/hr.
Answer:
Q = 4.52 10¹⁷ J
Explanation:
Thermal energy can be calculated with
Q = m c_{e} ΔT
in this case it indicates that we approximate seawater to pure water with
c_{e} = 4186 J/ kg K
with the density
ρ = m / V
m = ρ V
V = L³
we substitute
m = ρ L³
Q = ρ L3 c_{e} ΔT
calculate
Q = 1000 (3 103) 3 4186 4
Q = 4.52 10¹⁷ J