To get the probability of two individual events both occurring,
you have to multiply the probabilities of their individual events occurring. Therefore
in this problem, the probability that a student selected at random will pass
both French 101 and French 102 is 0.683 (.75 x .91). The answer is already
rounded to three decimal places.
Answer:
60
Step-by-step explanation:
Answer:
Either 0 or 1/7 depending upon the context, need more information
Fist we find the legnth of the diagonal
a^2+b^2=c^2
3^2+4^2=c^2
9+16=c^2
25=c^2
c=5
now the other diagonal
11^2+5^2=c^2
121+25=c^2
146=c^2
sqrt both sides12.083
closest is B
Answer:
8r^4
Step-by-step explanation:
√(64r^8) = √((8r^4)^2) = 8r^4
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You can make use of either or both of these rules of exponents:
(a^b)^c = a^(b·c) . . . . . used above
![\sqrt[n]{a}=a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Using the second rule, you can write the expression as ...
