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STALIN [3.7K]
3 years ago
10

the probability density for a particle in a box is an oscillatory function even for very large energies. Explain how the classic

al limit of a constant probability density that is independent of position is achieved
Mathematics
1 answer:
77julia77 [94]3 years ago
8 0

Answer:

This is achieved for the specific case when high quantum number with low resolution is present.

Step-by-step explanation:

In Quantum Mechanics, the probability density defines the region in which the  likelihood of finding the particle is most.

Now for the particle in the box, the probability density is also dependent on resolution as well so for large quantum number with small resolution, the oscillations will be densely packed and thus indicating in the formation of a constant probability density throughout similar to that of classical approach.

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A grapefruit has a peel that is 1cm thick and a total diameter of 12cm. What percentage of volume of the grapefruit is the peel?
ira [324]

Answer:

0.3056 or 30.56%

Step-by-step explanation:

The volume of the grapefruit with the peel is:

V_p=\frac{4 \pi (d/2)^2}{3}\\V_p=\frac{4 \pi (12/2)^2}{3}\\V_p=48 \pi

When removing the peel, the grapefruit diameter becomes 10 cm (take out 1 cm of peel from each side). The volume of the grapefruit without the peel is:

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The percentage of the volume correspondent to the peel is given by the difference between both volumes, divided by the total volume:

\%P = \frac{48\pi - 33.333\pi}{48\pi}\\ \%P =0.3056 = 30.56\%

30.56% of volume of the grapefruit is the peel.

4 0
3 years ago
I need help please with this math problem.
dezoksy [38]

Answer:

They are equal

Both answer is 65

Step-by-step explanation:

5x -30 = 2x +27

5x -2x = 27 +30

3x = 57

x = 57/3 = 19

5x -30 = 5(19) -30 = 65

2x +27 = 2(19) +27 = 65

5 0
3 years ago
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