Answer:
eighths
8
32
Step-by-step explanation:
i took the test on edu.
Answer:
Probability that in a random sample of six cities, the sample mean would be more than 40 is 0.3372.
Step-by-step explanation:
We are given that the percent of births to mothers with less than a college education in all of the most populated cities in the U.S. has an average of 39.3 with a standard deviation of 4.1.
Assuming the data follows distribution. Also, a random sample of six cities is selected.
<em>Firstly, Let </em>
<em> = sample mean of six cities</em>
The z score probability distribution for sample mean is given by;
Z =
~ N(0,1)
where,
= average percent of births = 39.3
= standard deviation = 4.1
n = sample of cities = 6
Probability that in a random sample of six cities, the sample mean would be more than 40 is given by = P(
> 40)
P(
> 40) = P(
>
) = P(Z > 0.42) = 1 - P(Z
0.42)
= 1 - 0.66276 = 0.3372
Therefore, probability that the sample mean would be more than 40 is 0.3372.
Standard form is ax+by=c, we like a and b to be integers, we also like a to be positive
basically get x and y on one side
so
y-4=(3/4)(x+8)
distribte the 3/4
y-4=(3/4)x+6
minus 3/4x from both sides
-(3/4)x+y-4=6
add 4 to both sides
(-3/4)x+y=10
times both sides by -4
3x-4y=-40
Answer:
1\7
Step-by-step explanation:
The n-th term of a geometric sequence with initial value a and common ratio r is given by
.
We have
and
and ![n=12](https://tex.z-dn.net/?f=n%3D12)
Substitute:
![a_{12}=-2\cdot3^{12-1}=-2\cdot3^{11}=-2\cdot177147=-354294](https://tex.z-dn.net/?f=a_%7B12%7D%3D-2%5Ccdot3%5E%7B12-1%7D%3D-2%5Ccdot3%5E%7B11%7D%3D-2%5Ccdot177147%3D-354294)