All categories

3 years ago

A sample of gas X occupies 10 mº at a pressure of 120 kPa.

Chemistry

1 answer:

Mashutka [201]3 years ago

5 0

Answer:

The new pressure of the gas comes out to be 400 KPa.

Explanation:

Initial volume of gas = V = $10\textrm{ m}^{3}$

Initial pressure of gas = P = 120 KPa

Final volume of gas = V' = $3\textrm{ m}^{3}$

Assuming temperature to be kept constant.

Assuming final pressure of the gas to be P' KPa

$PV = P'V' \\120\textrm{ KPa}\times 10\textrm{ m}^{3} = \textrm{P'}\times 3\textrm{ m}^{3} \\\textrm{P'} = 400\textrm{ KPa}$

New pressure of gas = 400 KPa

You might be interested in

2. Heat is:

nlexa [21]

A. Thermal energy good job

5 0

3 years ago

Read 2 more answers

A substance freezes at -58 celcius. Therefore a substance melts at: ________________

Liono4ka [1.6K]

-58 °C
The melting point is the same as the freezing point.

4 0

3 years ago

(e) Another student investigated the rate of a different reaction

vodka [1.7K]

Answer:

0.07 g/s.

Explanation:

From the question given above, the following data were obtained:

Mass lost = 9.85 g

Time taken = 2 min 30 s

Mean rate =?

Next, we shall convert 2 min 30 s to seconds (s). This can be obtained as follow:

1 min = 60 s

Thus,

2 min = 2 × 60 = 120 s

Therefore,

2 min 30 s = 120 s + 30 s = 150 s

Finally, we shall determine the mean rate of the reaction. This can be obtained as illustrated below:

Mass lost = 9.85 g

Time taken = 150 s

Mean rate =?

Mean rate = mass lost / time taken

Mean rate = 9.85 / 150

Mean rate = 0.07 g/s

Therefore, the mean rate of the reaction is 0.07 g/s

4 0

3 years ago

calculate pressure exerted by 1.255 mol of CI2 in a volume of 5.005 L at a temperature 273.5 k using ideal gas equation

balu736 [363]

Answer:

The pressure is 5.62 atm.

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

In this case: